Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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Sine is positive and cosine is strictly decreasing on (0,2), with cos 2 at most -1/3

Statement

For 0<x≤2, sin⁡x≥x−x3/6≥x/3>0. Also cos⁡2≤−1/3. Consequently cos⁡ is strictly decreasing on [0,2].

Facts & Assumptions

Proof

technique · direct
1.1

The absolute sine terms after the first have successive ratio at most 4/6<1, so [L2] gives sin⁡x≥x−x3/6≥x/3>0.

L1L2algebra
1.2

In the cosine series at 2, the first three terms sum to 1−2+2/3=−1/3, and the remaining alternating tail begins negative with decreasing absolute terms; hence cos⁡2≤−1/3.

L1L2algebra
2.1

On (0,2) one has cos⁡′=−sin⁡<0 by step 1.1, so the mean value theorem makes cos⁡ strictly decreasing on [0,2].

step 1.1L3∎

Depends on

Used by

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources