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Boundedness of the SIPDG form in the augmented norm

Statement

Assume Countable Choice and the SIPDG setting of Symmetric interior-penalty DG form and energy seminorm, with γ>0. For all v,w∈Dh, ∣ah(v,w)∣≤CB∥v∥DG,∗∥w∥DG,∗,CB:=2+2γ−1/2. The energy expression ∥⋅∥DG is also a seminorm on Dh.

Facts & Assumptions

Given: Countable Choice, the SIPDG form and augmented expression on Dh, and γ>0.

[F1]

Symmetric interior-penalty DG form and energy seminorm: ah is the cell coefficient-gradient term, two symmetric flux-jump terms, and the penalty term; ∥⋅∥DG,∗2 adds ∑FhF∥qF(⋅)∥L2(F)2 to the energy expression.

[F2]

Holder's inequality for integrals, including the endpoint cases: for L2 functions, ∣∫fg∣≤∥f∥2∥g∥2.

[F4]

The Axiom of Countable Choice (ACω): Countable Choice is the declared Sobolev/trace background of the form definition [F1].

Proof

1.1F1F2F3F4givenalgebra

Set X(v)2:=∑K∫K∇vTAK∇v dx and J(v)2:=∑FhF−1∥[v]F∥L2(F)2. For any real vectors ξ,η, positivity of AK gives (ξ+tη)TAK(ξ+tη)≥0 for every real t; the discriminant of this quadratic implies ∣ξTAKη∣≤(ξTAKξ)1/2(ηTAKη)1/2. Applying [F2] on each cell and then [F3] to the finite cell sum gives ∣∑K∫K∇vTAK∇w∣≤X(v)X(w). The same two inequalities give ∣γ∑FhF−1∫F[v]F[w]F∣≤γJ(v)J(w). Applying [F3] to the two-component vectors (X(v),γJ(v)) and (X(w),γJ(w)) shows that the absolute value of the sum of the volume and penalty terms is at most ∥v∥DG∥w∥DG≤∥v∥DG,∗∥w∥DG,∗.

2.1F1F2F3step 1.1algebra

For one flux term, weighted Cauchy–Schwarz using [F2] on each face and [F3] on the finite face sum gives ∣∑F∫FqF(v)[w]F∣≤(∑FhF∥qF(v)∥22)1/2J(w)≤γ−1/2∥v∥DG,∗∥w∥DG,∗. Interchanging v,w gives the same bound for the other flux term. Adding these two bounds to step 1.1 proves the stated bilinear-form constant.

3.1F1step 1.1algebra∎

The energy pairing bDG(v,w):=∑K∫K∇vTAK∇w+γ∑FhF−1∫F[v]F[w]F is symmetric and nonnegative on the diagonal. Step 1.1 proves ∣bDG(v,w)∣≤∥v∥DG∥w∥DG. Expanding bDG(v+w,v+w) and using this bound gives ∥v+w∥DG2≤(∥v∥DG+∥w∥DG)2; the formula also gives nonnegativity and absolute homogeneity. Taking square roots proves the seminorm axioms.

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