How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Boundedness of the SIPDG form in the augmented norm
Statement
Assume Countable Choice and the SIPDG setting of Symmetric interior-penalty DG form and energy seminorm, with . For all , The energy expression is also a seminorm on .
Facts & Assumptions
Given: Countable Choice, the SIPDG form and augmented expression on , and .
Symmetric interior-penalty DG form and energy seminorm: is the cell coefficient-gradient term, two symmetric flux-jump terms, and the penalty term; adds to the energy expression.
Holder's inequality for integrals, including the endpoint cases: for functions, .
Cauchy-Schwarz with its equality case, the triangle inequality for , the parallelogram law and polarisation: the Euclidean Cauchy–Schwarz inequality holds for every finite list.
The Axiom of Countable Choice (): Countable Choice is the declared Sobolev/trace background of the form definition [F1].
Proof
Set and . For any real vectors , positivity of gives for every real ; the discriminant of this quadratic implies . Applying [F2] on each cell and then [F3] to the finite cell sum gives . The same two inequalities give . Applying [F3] to the two-component vectors and shows that the absolute value of the sum of the volume and penalty terms is at most .
For one flux term, weighted Cauchy–Schwarz using [F2] on each face and [F3] on the finite face sum gives . Interchanging gives the same bound for the other flux term. Adding these two bounds to step 1.1 proves the stated bilinear-form constant.
The energy pairing is symmetric and nonnegative on the diagonal. Step 1.1 proves . Expanding and using this bound gives ; the formula also gives nonnegativity and absolute homogeneity. Taking square roots proves the seminorm axioms.
Depends on
- Symmetric interior-penalty DG form and energy seminorm
- Holder's inequality for integrals, including the endpoint cases
- Cauchy-Schwarz $\lvert\langle x,y\rangle\rvert \le \lVert x\rVert_2\lVert y\rVert_2$ with its equality case, the triangle inequality for $\lVert\cdot\rVert_2$, the parallelogram law and polarisation
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Dependency tree · two levels
36 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Jean-Luc Guermond, MATH 661 Fall 2025, Part VIII, Chapter 38: Discontinuous Galerkin (standard reference, not scraped)
- Douglas N. Arnold, Franco Brezzi, Bernardo Cockburn, and L. Donatella Marini, Unified Analysis of Discontinuous Galerkin Methods for Elliptic Problems, SIAM Journal on Numerical Analysis 39(5) (2002) (standard reference, not scraped)