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Symmetric interior-penalty discontinuous Galerkin

1 · Prerequisites

2 · Summary

This page defines the symmetric interior-penalty method for scalar, real, second-order elliptic diffusion on finite matching shape-regular affine simplicial meshes, with a piecewise constant symmetric positive-definite coefficient and homogeneous Dirichlet data imposed weakly. The local inverse-trace result yields a sufficient degree- and shape-dependent penalty threshold; no universal value is claimed. The energy estimate is proved directly from SIP consistency and coercivity. The L2 estimate is conditional on adjoint consistency, dual regularity, and a face-aware approximation bound with exponent s>1/2. Equilibrated H(div⁡) flux recovery is outside this interface.

3 · Logical flowchart

4 · Definitions, theorems and proofs

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Sobolev traces and Gauss–Green formula on physical simplices

Statement

Assume Countable Choice. Let d≥2, let S^d be the reference simplex, and let FK(x^)=b+Bx^ map S^d‾ affinely onto a nondegenerate closed simplex K, with det⁡B>0. Sobolev spaces on K mean spaces on its open interior. For every scalar u∈W1,2(K) and vector field G∈W1,2(K;Rd), each physical facet has bounded L2 traces γFu and γFG, obtained by affine transfer from the reference trace maps. These traces are independent of the chosen orientation-preserving reference map, and they satisfy ∫Ku div⁡G+∇u⋅G dx=∑F⊂∂K∫F(γFu)(γFG)⋅nK,F dS, where nK,F is the outward unit normal.

Facts & Assumptions

Given: Countable Choice, the reference simplex, an orientation-preserving affine map onto a nondegenerate simplex, u∈W1,2(K), and G∈W1,2(K;Rd).

[F1]

Matching affine simplicial meshes and shape regularity: every physical cell is the image of the reference simplex by an affine bijection; its vertex order is chosen so the map has positive determinant.

[F2]

Affine pullback of weak derivatives and Sobolev seminorms: affine pullbacks of W1,2 functions lie in W1,2 and satisfy ∇x^(v∘F)=BT(∇xv)∘F.

[F3]

Sobolev face traces and Gauss–Green on a reference simplex: scalar and componentwise vector traces from W1,2(S^d) to L2(F^) exist on every reference facet and obey the reference Gauss–Green identity.

[F4]

Gauss–Green formula on an affine simplex: the oriented face area element transforms as nK,F dS=det⁡(B)B−Tn^F^ dS^.

[F5]

Smooth functions are dense in finite-order Sobolev spaces on a reference simplex: restrictions of smooth functions on a neighborhood of the closed reference simplex are dense in W1,2(S^d).

[F6]

A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions: under the affine map, volume integrals transform with the constant Jacobian det⁡(B)>0.

[F7]

Holder's inequality for integrals, including the endpoint cases: products of two L2 functions on a measure space are integrable and their integrals satisfy the L2 Cauchy–Schwarz bound.

[F8]

The Axiom of Countable Choice (ACω): Countable Choice is the declared hypothesis of the affine pullback, density, change-of-variables, and reference trace suppliers [F2]–[F3], [F5]–[F6].

Proof

1.1F1F2F3F4F5F8given

Put u^=u∘FK and G^=det⁡(B)B−1(G∘FK). By [F2], both belong to W1,2(S^d). Define the physical traces by γFu(FK(x^))=γF^u^(x^) and γFG(FK(x^))=(det⁡B)−1BγF^G^(x^). The reference traces in [F3] are in L2(F^); the constant affine surface Jacobian det⁡(B)∣B−Tn^F^∣>0 from [F4] and the fixed matrix factor show these definitions give bounded L2(F) traces. For a fixed map, [F5] supplies smooth approximants to u^ and each component of G∘FK; the reverse estimate in [F2] maps them to smooth approximants on K. Thus smooth functions on K are dense in W1,2(K), and any two bounded affine-transfer trace maps agree on this dense smooth class, so they agree on all of W1,2(K).

2.1F2F3F4F6F7F8step 1.1algebra∎

Applying the componentwise weak chain rule [F2] and the identity ∑jBℓj(B−1)ji=δℓi gives div⁡x^G^=det⁡(B)(div⁡xG)∘FK. Also ∇x^u^⋅G^=((BT∇xu)∘FK)⋅(det⁡(B)B−1(G∘FK))=det⁡(B)(∇xu⋅G)∘FK. The volume products are integrable by [F7], so [F6] applied to their positive and negative parts identifies the reference volume integral in [F3] with the physical volume integral in the claim. The reference boundary products are integrable by [F3] and [F7]. By the trace definition in step 1.1, γF^G^=det⁡(B)B−1(γFG)∘FK; hence its normal pairing is det⁡(B)(γFG)⋅B−Tn^F^ dS^=(γFG)⋅nK,F dS by [F4], while the scalar trace is the pullback of γFu. Applying [F3] and summing over the finitely many facets proves the identity.

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Jump and average conventions for symmetric interior-penalty DG

Definition

Let d≥2 and let T be a finite matching affine simplicial mesh of a bounded polyhedral open set Ω⊂Rd, with shape-regularity bound σ, as in Matching affine simplicial meshes and shape regularity. Write Fhint for its interior facets and Fhbdy for its boundary facets, and put Fh=Fhint∪Fhbdy. Fix a degree k∈N0 for this broken space. The trial functions below belong to the broken scalar polynomial space Vhbr=∏K∈TPk(K;R) from Broken and conforming polynomial spaces on a matching mesh.

For each interior facet F=K−∩K+, choose a unit normal nF pointing from K− to K+. For a scalar or vector field g with traces from both cells, define [g]F:=g−−g+,{g}F:=12(g−+g+). For a boundary facet F⊂∂K∩∂Ω, let nF=nK be the outward unit normal and define [g]F:=g∣K and {g}F:=g∣K. Reversing the chosen interior normal also reverses [g]F, so the scalar jump/average contractions used in the form are independent of that choice.

For one-dimensional interval examples, use the following separate extension of the same formulas. At an interior point shared by a left cell K− and right cell K+, orient from left to right and set [g]F=g−−g+ and {g}F=(g−+g+)/2. At either endpoint use the one-sided trace for both jump and average, and use counting measure on the zero-dimensional face. This extension is not an instance of the published d≥2 mesh definition above.

The following diagram records the interior orientation; the formulas above are the definitions, and the diagram is only a convention aid.

nFK¡K+F

Remarks

This is the scalar-jump convention: on an interior facet the corresponding vector jump is [v]FnF. On a boundary facet the jump is the trace itself; this is the convention that makes the penalty and consistency terms impose homogeneous Dirichlet data weakly. A normal-flux contraction with the scalar jump is unchanged when the interior orientation is reversed.

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Symmetric interior-penalty DG form and energy seminorm

Definition

Assume Countable Choice for the Sobolev notation below. Each cell K is the closed simplex from Matching affine simplicial meshes and shape regularity; in Wm,2(K) notation, K means its open interior, and its facets are the boundary faces of that interior. Write Hm(K):=Wm,2(K;R) for m=1,2. Use the mesh and jump convention of Jump and average conventions for symmetric interior-penalty DG. Specialize Broken and conforming polynomial spaces on a matching mesh to scalar real polynomials of a fixed degree k≥1, so Vhbr=∏K∈TPk(K;R). On every cell K, let AK∈Rd×d be a constant symmetric matrix. Assume common bounds 0<λ≤Λ<∞ such that λ∣ξ∣2≤ξTAKξ≤Λ∣ξ∣2(ξ∈Rd, K∈T). Write A∣K=AK, let hF:=diam⁡(F)>0, and fix a penalty parameter γ>0. Define Dh to consist of broken real-valued functions v with v∣K∈H1(K), distributional div⁡(AK∇v∣K)∈L2(K), and an L2(F) one-sided normal coefficient-flux trace rK,F(v) on every facet F of each cell K. Precisely, rK,F(v) is the unique L2(F) function satisfying ∫KAK∇v⋅∇ϕ+div⁡(AK∇v) ϕ dx=∑F⊂∂K∫FrK,F(v) γFϕ dS(ϕ∈C∞(K‾)). Here γFϕ is the value trace from Sobolev traces and Gauss–Green formula on physical simplices; uniqueness follows by testing smooth functions supported near the relative interior of each facet, whose restrictions are dense in L2(F). If F=K−∩K+ and nF points outward from K−, set qF(v):=12(rK−,F(v)−rK+,F(v)); on a boundary facet set qF(v):=rK,F(v) with the outward normal. These definitions agree with {A∇hv}F⋅nF whenever the classical one-sided vector flux traces exist. Broken polynomials and cellwise H2 functions belong to Dh by Sobolev traces and Gauss–Green formula on physical simplices. For v,w∈Dh, define ah(v,w):=∑K∈T∫KAK∇v⋅∇w dx−∑F∈Fh∫FqF(v)[w]F dS−∑F∈Fh∫FqF(w)[v]F dS+γ∑F∈FhhF−1∫F[v]F[w]F dS, All facet integrals and L2(F) norms use (d−1)-dimensional surface measure for the stated mesh dimension d≥2. Counting measure is reserved for the separate one-dimensional interval examples in Jump and average conventions for symmetric interior-penalty DG. The expression is real and symmetric.

Define the energy expression and its augmented version on Dh by ∥v∥DG2:=∑K∈T∫KAK∇v⋅∇v dx+γ∑F∈FhhF−1∥[v]F∥L2(F)2, ∥v∥DG,∗2:=∥v∥DG2+∑F∈FhhF∥qF(v)∥L2(F)2. The first expression is initially a seminorm on Vhbr; its definiteness is not part of this definition. The stated Sobolev notation follows Integer-order Sobolev spaces and their norms. Cellwise H2 functions have the required value and normal coefficient-flux traces by Sobolev traces and Gauss–Green formula on physical simplices, because AK is constant. The augmented expression is defined whenever v∈Dh, so it applies in particular to the exact functions, dual functions and discrete polynomials used below.

For f∈L2(Ω) define the discrete load ℓh(w):=∑K∈T∫Kfw dx. A symmetric interior-penalty DG solution is a function uh∈Vhbr satisfying ah(uh,wh)=ℓh(wh) for every wh∈Vhbr.

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Discrete inverse-trace bound for SIPDG coefficient fluxes

Statement

Assume Countable Choice. Let T, AK, k, λ, Λ, hF, and qF be as in Symmetric interior-penalty DG form and energy seminorm. There is a constant Cflux<∞, depending only on d, k, σ, λ, and Λ, such that every vh∈Vhbr satisfies ∑F∈FhhF∥qF(vh)∥L2(F)2≤Cflux∑K∈T∫KAK∇vh⋅∇vh dx. The constant is uniform over the mesh family and does not depend on its cell sizes. In particular, the penalty threshold derived from this estimate is mesh-degree and shape dependent; it is not a universal numerical constant.

Facts & Assumptions

Given: Countable Choice; a shape-regular affine simplicial mesh with bound σ; k≥1; piecewise constant symmetric coefficients satisfying λI≤AK≤ΛI; and vh∈Vhbr.

[F1]

The SIPDG definition gives qF(vh) as the arithmetic average of the adjacent coefficient fluxes, dotted with the fixed face normal; the boundary flux is one-sided. (Symmetric interior-penalty DG form and energy seminorm)

[F2]

For every cell polynomial and facet, the discrete trace estimate has scaling ∥g∥L2(F)≤ChK−1/2∥g∥L2(K); constants depend on degree and shape regularity. (Polynomial inverse and discrete trace inequalities)

[F3]

The inverse-trace supplier explicitly assumes Countable Choice. (The Axiom of Countable Choice (ACω))

[A1]

Since F⊂K and hF=diam⁡(F), hF≤hK for every incident cell.

Proof

1.1F1F2F3A1given

For each cell K, AK∇(vh∣K) is a vector polynomial of degree at most k−1. Let Cinv be d times the trace constant in [F2] with polynomial degree k−1, so the estimate applies componentwise. Use ∣AKξ∣≤Λ∣ξ∣. For an interior face, convexity of the squared norm gives ∣{A∇hvh}∣2≤12(∣AK−∇vh−∣2+∣AK+∇vh+∣2); for a boundary face there is one term. By [A1], hF≤hK, so hF∥qF(vh)∥L2(F)2≤Cinv2Λ2∑K∈TF∥∇vh∥L2(K)2, where TF is the set of one or two incident cells.

2.1step 1.1givenalgebra∎

Each simplex has d+1 facets, so summing step 1.1 over all faces counts each cell at most d+1 times. Ellipticity gives ∑K∥∇vh∥L2(K)2≤λ−1∑K∫KAK∇vh⋅∇vh. Thus the required estimate holds with Cflux:=(d+1)Cinv2Λ2/λ.

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The SIPDG broken energy expression is definite

Statement

Assume Countable Choice. Let ∥⋅∥DG be the energy expression from Symmetric interior-penalty DG form and energy seminorm on a finite matching simplicial mesh of a nonempty bounded polyhedral domain, with λ>0 and γ>0. Then ∥⋅∥DG is a norm on Vhbr.

Facts & Assumptions

Given: Countable Choice; a finite face-to-face triangulation of a bounded polyhedral open set, λ>0, γ>0, and the broken polynomial space and energy expression of Symmetric interior-penalty DG form and energy seminorm.

[F1]

The squared energy expression is the sum of nonnegative cell-gradient terms and positive-weight squared jumps on every interior and boundary facet. (Symmetric interior-penalty DG form and energy seminorm)

[F2]

A matching mesh is a finite union of nondegenerate simplices with pairwise-disjoint interiors; each interior facet is shared and each boundary facet is exterior. (Matching affine simplicial meshes and shape regularity)

[F3]

Products of L2 functions satisfy the integral Cauchy–Schwarz inequality. (Holder's inequality for integrals, including the endpoint cases)

[F5]

On each physical simplex, the Green identity applies to u=1 and the vector field G(x)=x, giving d∣K∣=∑F⊂∂K∫Fx⋅nK,F dS. (Sobolev traces and Gauss–Green formula on physical simplices)

[F6]

Countable Choice is the declared Sobolev/trace background of [F1] and the physical-simplex Green supplier [F5]. (The Axiom of Countable Choice (ACω))

Proof

1.1F1givenalgebra

Suppose ∥vh∥DG=0. Every cell-gradient term is zero, and positive definiteness of AK implies ∇(vh∣K)=0 almost everywhere. Since vh∣K is a polynomial on the connected simplex K, it is a constant cK.

2.1F1F2F5F6step 1.1algebra

Every interior-facet jump is zero by [F1], so adjacent cells have equal constants. Thus cK is constant on each connected component of the cell-facet adjacency graph. For any such component, sum [F5] over its finitely many cells. The cell volumes are positive, while the two oriented integrals on every shared facet cancel; if there were no unshared facet, this would give d∑K∣K∣=0, a contradiction. Every unshared facet is an exterior mesh facet by the matching property [F2]. On that facet the boundary jump is the cell trace itself, so [F1] forces the component's constant to be zero. Therefore vh=0 on every cell.

3.1F1F2F3F4step 2.1algebra∎

The expression is homogeneous under scalar multiplication. Define its associated pairing by bDG(vh,wh):=∑K∫K∇vhTAK∇wh+γ∑FhF−1∫F[vh]F[wh]F. For any vectors ξ,η, the quadratic (ξ+tη)TAK(ξ+tη) is nonnegative for all real t; if η≠0, its discriminant is nonpositive, giving ∣ξTAKη∣≤(ξTAKξ)1/2(ηTAKη)1/2, and the case η=0 is immediate. [F3] bounds the resulting cell integrals and each facet integral, while [F4] combines the finitely many cell and facet terms to give ∣bDG(vh,wh)∣≤∥vh∥DG∥wh∥DG. Expanding bDG(vh+wh,vh+wh) gives ∥vh+wh∥DG2≤(∥vh∥DG+∥wh∥DG)2. Thus the triangle inequality holds; together with step 2.1 this proves the norm axioms.

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Boundedness of the SIPDG form in the augmented norm

Statement

Assume Countable Choice and the SIPDG setting of Symmetric interior-penalty DG form and energy seminorm, with γ>0. For all v,w∈Dh, ∣ah(v,w)∣≤CB∥v∥DG,∗∥w∥DG,∗,CB:=2+2γ−1/2. The energy expression ∥⋅∥DG is also a seminorm on Dh.

Facts & Assumptions

Given: Countable Choice, the SIPDG form and augmented expression on Dh, and γ>0.

[F1]

Symmetric interior-penalty DG form and energy seminorm: ah is the cell coefficient-gradient term, two symmetric flux-jump terms, and the penalty term; ∥⋅∥DG,∗2 adds ∑FhF∥qF(⋅)∥L2(F)2 to the energy expression.

[F2]

Holder's inequality for integrals, including the endpoint cases: for L2 functions, ∣∫fg∣≤∥f∥2∥g∥2.

[F4]

The Axiom of Countable Choice (ACω): Countable Choice is the declared Sobolev/trace background of the form definition [F1].

Proof

1.1F1F2F3F4givenalgebra

Set X(v)2:=∑K∫K∇vTAK∇v dx and J(v)2:=∑FhF−1∥[v]F∥L2(F)2. For any real vectors ξ,η, positivity of AK gives (ξ+tη)TAK(ξ+tη)≥0 for every real t; the discriminant of this quadratic implies ∣ξTAKη∣≤(ξTAKξ)1/2(ηTAKη)1/2. Applying [F2] on each cell and then [F3] to the finite cell sum gives ∣∑K∫K∇vTAK∇w∣≤X(v)X(w). The same two inequalities give ∣γ∑FhF−1∫F[v]F[w]F∣≤γJ(v)J(w). Applying [F3] to the two-component vectors (X(v),γJ(v)) and (X(w),γJ(w)) shows that the absolute value of the sum of the volume and penalty terms is at most ∥v∥DG∥w∥DG≤∥v∥DG,∗∥w∥DG,∗.

2.1F1F2F3step 1.1algebra

For one flux term, weighted Cauchy–Schwarz using [F2] on each face and [F3] on the finite face sum gives ∣∑F∫FqF(v)[w]F∣≤(∑FhF∥qF(v)∥22)1/2J(w)≤γ−1/2∥v∥DG,∗∥w∥DG,∗. Interchanging v,w gives the same bound for the other flux term. Adding these two bounds to step 1.1 proves the stated bilinear-form constant.

3.1F1step 1.1algebra∎

The energy pairing bDG(v,w):=∑K∫K∇vTAK∇w+γ∑FhF−1∫F[v]F[w]F is symmetric and nonnegative on the diagonal. Step 1.1 proves ∣bDG(v,w)∣≤∥v∥DG∥w∥DG. Expanding bDG(v+w,v+w) and using this bound gives ∥v+w∥DG2≤(∥v∥DG+∥w∥DG)2; the formula also gives nonnegativity and absolute homogeneity. Taking square roots proves the seminorm axioms.

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Exact consistency of the symmetric interior-penalty DG form

Statement

Assume Countable Choice. Let the mesh, coefficients, and SIPDG form be as in Symmetric interior-penalty DG form and energy seminorm. Suppose u∣K∈H2(K) on every cell, its facet traces agree across every interior facet, its boundary trace is zero, and f∣K=−∇⋅(AK∇u) on each cell with f∈L2(Ω). Assume also that the normal coefficient fluxes agree across interior facets: (AK−∇u−)⋅nF=(AK+∇u+)⋅nF. Then for every wh∈Vhbr, ah(u,wh)=ℓh(wh):=∑K∈T∫Kfwh dx.

Facts & Assumptions

Given: Countable Choice; a finite matching affine simplicial mesh; cellwise constant symmetric positive-definite AK; a piecewise H2 function u with matching interior traces and zero boundary trace; a piecewise L2 source f=−∇⋅(AK∇u); and matching interior normal fluxes.

[F1]

The SIPDG form contains the broken volume term, the two symmetric flux-jump terms, and the jump penalty; the boundary jump equals the trace of its cell. (Symmetric interior-penalty DG form and energy seminorm, Jump and average conventions for symmetric interior-penalty DG)

[F2]

On each physical affine simplex, for scalar v∈W1,2 and vector field G∈W1,2, the transferred face traces satisfy ∫Kv div⁡G+∇v⋅G=∑F⊂∂K∫F(γFv)(γFG)⋅nK,F. (Sobolev traces and Gauss–Green formula on physical simplices)

[F3]

Countable Choice is the stated hypothesis of the physical-simplex trace and Green identity [F2]. (The Axiom of Countable Choice (ACω))

[F4]

H2(K) means W2,2(K) and W1,2(K) consists of L2 classes with first weak derivatives in L2. (Integer-order Sobolev spaces and their norms)

Proof

1.1F1F2F3F4given

On each cell K, take v=wh∣K and G=AK∇u. Since u∣K∈H2(K), [F4] and constant AK give G∈W1,2(K;Rd), so [F2] and the cell equation yield ∫KAK∇u⋅∇wh=∫Kfwh+∑F⊂∂K∫F(AK∇u⋅nK,F)wh∣K.

2.1F1step 1.1givenalgebra

Sum step 1.1 over cells. On an interior facet the two outward normals are nF and −nF; the assumed normal-flux equality makes the two boundary terms equal ∫FqF(u)[wh]F. On a boundary facet the single term is also ∫FqF(u)[wh]F by the one-sided convention. Therefore the broken volume term equals ℓh(wh)+∑F∫FqF(u)[wh]F.

3.1F1step 2.1givenalgebra∎

The matching traces of u and its zero boundary trace give [u]F=0 on every facet. Substitution into the SIPDG form makes its second flux-jump term exactly cancel the face sum of step 2.1, while its adjoint-consistency term and penalty term vanish. Hence ah(u,wh)=ℓh(wh).

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SIPDG adjoint consistency for piecewise H2 dual solutions

Statement

Assume Countable Choice and the mesh and coefficient hypotheses of Symmetric interior-penalty DG form and energy seminorm. Let e∣K∈H2(K) on every cell, and let z∣K∈H2(K) be a dual solution with matching interior traces, zero boundary trace, matching normal coefficient fluxes, and −∇⋅(AK∇z)=e on every cell. Then the SIPDG form, extended to these piecewise regular functions by its same formula, satisfies ah(e,z)=∥e∥L2(Ω)2.

Facts & Assumptions

Given: Countable Choice; a finite matching affine simplicial mesh; piecewise constant symmetric positive-definite AK; piecewise H2 error e; and a piecewise H2 dual solution z with matching traces, zero boundary trace, matching normal fluxes, and −∇⋅(AK∇z)=e cellwise.

[F1]

The SIPDG formula is symmetric in its two arguments, with face terms −qF(v)[w]F−qF(w)[v]F+γhF−1[v]F[w]F. (Symmetric interior-penalty DG form and energy seminorm)

[F2]

For v,G∈W1,2 on a physical affine simplex, the trace Green identity is ∫Kv div⁡G+∇v⋅G=∑F⊂∂K∫F(γFv)(γFG)⋅nK,F. (Sobolev traces and Gauss–Green formula on physical simplices)

[F3]

Countable Choice is required by the imported reference-simplex Green identity [F2]. (The Axiom of Countable Choice (ACω))

[F4]

H2(K) means W2,2(K), so AK∇z∈W1,2(K;Rd) when AK is constant. (Integer-order Sobolev spaces and their norms)

Proof

1.1F1F2F3F4given

On each cell apply [F2] with scalar v=e∣K and vector field G=AK∇z, which belongs to W1,2 by [F4]. Symmetry of AK and the dual equation give ∫KAK∇e⋅∇z=∫Ke2+∑F⊂∂K∫Fe(AK∇z⋅nK,F).

2.1step 1.1givenalgebra

Sum step 1.1 over all cells. Matching normal fluxes make each interior-face contribution ∫FqF(z)[e]F, and the boundary contributions use [e]F=e. Thus ∑K∫KAK∇e⋅∇z=∥e∥L2(Ω)2+∑F∫FqF(z)[e]F.

3.1F1step 2.1givenalgebra∎

The traces of z match on interior facets and vanish on boundary facets, so [z]F=0 for every F. In ah(e,z) the term −qF(e)[z]F and the penalty term therefore vanish; the remaining flux term is −∑F∫FqF(z)[e]F. Substituting step 2.1 proves the identity.

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SIPDG coercivity above the discrete inverse-trace threshold

Statement

Assume Countable Choice. Use the mesh, coefficient field, energy norm, and form of Symmetric interior-penalty DG form and energy seminorm, and let Cflux be the constant of Discrete inverse-trace bound for SIPDG coefficient fluxes. If γ≥4Cflux, then ah(vh,vh)≥12∥vh∥DG2(vh∈Vhbr). Thus the discrete bilinear form is coercive with constant 1/2 in the broken energy norm. For every f∈L2(Ω), the finite-dimensional SIPDG system has a unique solution. The sufficient threshold depends on the polynomial degree, shape regularity, and coefficient ellipticity bounds; no universal penalty value is asserted.

Facts & Assumptions

Given: Countable Choice; k≥1; symmetric cellwise constant AK with ellipticity bounds 0<λ≤Λ; a finite matching shape-regular mesh; γ≥4Cflux; and the SIPDG form and energy norm.

[F1]

The form is the cell energy minus the two symmetric flux-jump pairings plus γ∑FhF−1([v]F,[w]F)L2(F). (Symmetric interior-penalty DG form and energy seminorm)

[F2]

The squared coefficient-flux trace satisfies ∑FhF∥qF(vh)∥L2(F)2≤Cflux∑K∫KAK∇vh⋅∇vh. (Discrete inverse-trace bound for SIPDG coefficient fluxes)

[F3]

The broken energy expression is a norm on the finite-dimensional discontinuous polynomial space. (The SIPDG broken energy expression is definite)

[F4]

Countable Choice is the explicit hypothesis in the inverse-trace and energy-norm suppliers [F2]–[F3]. (The Axiom of Countable Choice (ACω))

[F5]

The L2 case of Holder's inequality gives ∣∫Ffg dS∣≤∥f∥L2(F)∥g∥L2(F). (Holder's inequality for integrals, including the endpoint cases)

Proof

1.1F1F2F4F5F6algebra

Put X2:=∑K∫KAK∇vh⋅∇vh and J2:=∑FhF−1∥[vh]F∥L2(F)2. The integral Cauchy–Schwarz inequality [F5] on each facet, followed by [F6] on the finite weighted face sum and [F2] give ∣∑F∫FqF(vh)[vh]F∣≤(∑FhF∥qF(vh)∥F2)1/2J≤CfluxXJ.

2.1F1step 1.1givenalgebra

By [F1], ah(vh,vh)=X2−2∑F∫FqF(vh)[vh]F+γJ2. Young's inequality gives 2CfluxXJ≤12X2+2CfluxJ2, hence ah(vh,vh)≥12X2+(γ−2Cflux)J2≥12(X2+γJ2)=12∥vh∥DG2.

3.1givenF1F3step 2.1algebra∎

The coefficient matrix of ah in any basis of the finite-dimensional space Vhbr is symmetric by [F1]. If its matrix kernel contained a nonzero vector, the corresponding vh≠0 would satisfy ah(vh,vh)=0, contradicting [F3] and step 2.1. Therefore the square matrix is injective, hence invertible in finite dimension, so every load has exactly one solution.

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SIPDG L2 error under adjoint consistency and dual approximation

Statement

Assume Countable Choice and the SIPDG setting of Symmetric interior-penalty DG form and energy seminorm. Let u satisfy all hypotheses of Exact consistency of the symmetric interior-penalty DG form, and let uh∈Vhbr satisfy ah(uh,vh)=ℓh(vh) for all vh∈Vhbr. Set e:=u−uh, let V:=H01(Ω;R)=W01,2(Ω;R) as in Zero-boundary Sobolev space as a norm closure, and let h:=max⁡K∈ThK, with 0<h≤ℓΩ:=diam⁡(Ω). Suppose s∈(1/2,1] and a dual solution ze∈V exists satisfying ∑K∈T∫KAK∇v⋅∇ze dx=∫Ωve dx(v∈V), with the following properties:

  1. Its one-sided normal coefficient-flux traces are in L2(F) in the weak Green sense defining Dh. In the branch s=1, assume also ze∣K∈H2(K) on every cell, with matching interior value traces, zero boundary value trace, and matching interior normal coefficient fluxes; then SIPDG adjoint consistency for piecewise H2 dual solutions gives ah(e,ze)=∥e∥L2(Ω)2. In the branch s<1, assume this adjoint-consistency identity as an additional hypothesis. The weak dual equation gives div⁡(AK∇ze)∣K=−e∣K∈L2(K), so the stated flux and trace conditions place ze in the form domain Dh of Symmetric interior-penalty DG form and energy seminorm.
  2. The specified normed dual-regularity space Rs is a subspace of V∩Dh, and ∥ze∥Rs≤Creg∥e∥L2(Ω) for some Creg≥0.
  3. There is zh∈Vhbr such that ∥ze−zh∥DG,∗≤CapphsℓΩ1−s∥ze∥Rs. Here Capp≥0.

Then ∥e∥L2(Ω)≤(2+2γ−1/2)CappCreghsℓΩ1−s∥e∥DG,∗. The theorem retains the dual regularity exponent and the half-order face-flux contribution in ∥⋅∥DG,∗. It does not infer the dual approximation estimate or adjoint-consistency identity from elliptic regularity alone.

Facts & Assumptions

Given: Countable Choice; the exact solution u satisfying Exact consistency of the symmetric interior-penalty DG form and the discrete solution uh satisfying the equation in the Statement; the dual solution ze∈H01(Ω;R); an exponent s∈(1/2,1]; the branch-specific adjoint-consistency hypotheses in the Statement; the dual regularity and approximation inequalities in the Statement; and the augmented SIPDG expression.

[F1]

Exact consistency and the discrete equation imply ah(e,vh)=0 for every vh∈Vhbr. (Exact consistency of the symmetric interior-penalty DG form)

[F2]

On its form domain, the SIPDG bilinear form satisfies ∣ah(v,w)∣≤CB∥v∥DG,∗∥w∥DG,∗ with CB=2+2γ−1/2. (Boundedness of the SIPDG form in the augmented norm)

[F3]

In the s=1 branch, piecewise H2 dual solutions with matching traces and normal flux satisfy ah(e,ze)=∥e∥L2(Ω)2. (SIPDG adjoint consistency for piecewise H2 dual solutions)

[F4]

Countable Choice is the stated background for the exact-consistency, adjoint-consistency, physical-trace, and SIPDG form-domain suppliers used here. (The Axiom of Countable Choice (ACω))

[F5]

The zero-boundary space V is the norm closure of Cc∞(Ω) in W1,2(Ω), so a smooth test compactly supported inside a cell belongs to V. (Zero-boundary Sobolev space as a norm closure)

[F6]

The reference trace maps transfer to bounded value traces on each physical simplex facet for every cellwise W1,2 function. (Sobolev traces and Gauss–Green formula on physical simplices)

[F7]

The exact solution is cellwise H2 by the hypotheses of exact consistency, and the SIPDG definition places cellwise H2 functions and broken polynomials in Dh. (Exact consistency of the symmetric interior-penalty DG form, Symmetric interior-penalty DG form and energy seminorm)

[A1]

For s<1, the dual solution is assumed to have the stated weak L2 normal-flux traces and adjoint-consistency identity; this carrier does not prove the fractional trace theorem that would discharge those assumptions.

Proof

1.1F1F3F4A1givenchoose

The result is immediate if ∥e∥L2=0. Otherwise choose zh from the stated approximation hypothesis. For s=1, [F3] gives ah(e,ze)=∥e∥L22 under the stated piecewise-H2 and trace-matching hypotheses; for s<1 this identity is [A1]. Exact consistency plus the discrete equation give ah(e,zh)=0 by [F1]. Hence ∥e∥L22=ah(e,ze−zh).

1.2F2F4F5F6F7given

By [F7], u is cellwise H2 and uh,zh are broken polynomials, so e=u−uh and zh belong to Dh. For each cell K, a test in Cc∞(K) extended by zero belongs to V by [F5]; the weak dual equation then gives div⁡(AK∇ze)∣K=−e∣K∈L2(K) in distributions. Item 1 supplies the one-sided L2 normal flux traces, and ze∈V supplies its cellwise H1 restrictions and value traces by [F6]. Thus ze∈Dh and [F2] gives ∣ah(e,ze−zh)∣≤CB∥e∥DG,∗∥ze−zh∥DG,∗ with CB=2+2γ−1/2.

2.1step 1.1step 1.2givenalgebra∎

Apply step 1.2 to step 1.1 and then use the dual approximation and regularity assumptions. This gives ∥e∥L22≤CBCappCreghsℓΩ1−s∥e∥DG,∗∥e∥L2. Divide by the positive ∥e∥L2 to obtain the asserted estimate.

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A direct Strang-type energy error estimate for SIPDG

Statement

Assume Countable Choice and the mesh, coefficient, penalty, and exact-solution hypotheses of Exact consistency of the symmetric interior-penalty DG form and SIPDG coercivity above the discrete inverse-trace threshold. Let uh∈Vhbr be the unique discrete solution, so ah(uh,vh)=ℓh(vh) for every vh∈Vhbr. Let Cflux be the constant in Discrete inverse-trace bound for SIPDG coefficient fluxes and put CB:=2+2γ−1/2. Then for every wh∈Vhbr, ∥u−uh∥DG≤(1+2CB1+Cflux)∥u−wh∥DG,∗. Consequently ∥u−uh∥DG≤(1+2CB1+Cflux)inf⁡wh∈Vhbr∥u−wh∥DG,∗. The augmented approximation term retains the face-flux trace needed to bound the SIP consistency terms; no approximation rate is asserted without a separate bound on that term.

Facts & Assumptions

Given: Countable Choice; the exact solution u and discrete solution uh satisfying the equations in the Statement; the coercivity threshold; and the mesh-dependent expressions ∥⋅∥DG and ∥⋅∥DG,∗.

[F1]

The form and energy expressions are defined on Dh, which contains the cellwise H2 exact solution and the broken polynomials. (Symmetric interior-penalty DG form and energy seminorm)

[F2]

For γ≥4Cflux, ah(vh,vh)≥12∥vh∥DG2 on Vhbr. (SIPDG coercivity above the discrete inverse-trace threshold)

[F3]

For the stated piecewise H2 exact solution, ah(u,vh)=ℓh(vh) for every vh∈Vhbr. (Exact consistency of the symmetric interior-penalty DG form)

[F4]

For every zh∈Vhbr, ∑FhF∥qF(zh)∥L2(F)2≤Cflux∑K∫K∇zhTAK∇zh. (Discrete inverse-trace bound for SIPDG coefficient fluxes)

[F5]

The form obeys ∣ah(v,w)∣≤CB∥v∥DG,∗∥w∥DG,∗ on Dh, and ∥⋅∥DG is a seminorm there. (Boundedness of the SIPDG form in the augmented norm)

[F6]

Countable Choice is used by the inverse-trace and physical-simplex Green suppliers [F3]–[F4]. (The Axiom of Countable Choice (ACω))

Proof

1.1F1F5given

The exact solution u is cellwise H2 and uh,wh are broken polynomials, so u−wh and uh−wh belong to Dh. The boundedness constant for their form pairing is CB=2+2γ−1/2 by [F5].

2.1F1F2F3F4F5F6step 1.1givenalgebra

Fix wh and set zh=uh−wh. If ∥zh∥DG=0, then ∥zh∥DG≤2CB1+Cflux∥u−wh∥DG,∗ is immediate. Otherwise, coercivity [F2], the discrete equation and exact consistency [F3] give 12∥zh∥DG2≤ah(zh,zh)=ah(u−wh,zh). By [F4] and ∑K∫K∇zhTAK∇zh≤∥zh∥DG2, ∥zh∥DG,∗≤1+Cflux∥zh∥DG. Apply [F5] and step 1.1 to obtain 12∥zh∥DG2≤CB1+Cflux∥u−wh∥DG,∗∥zh∥DG. Dividing by ∥zh∥DG>0 proves ∥zh∥DG≤2CB1+Cflux∥u−wh∥DG,∗.

3.1F5step 2.1algebra∎

Since ∥⋅∥DG is a seminorm on Dh by [F5], its triangle inequality and step 2.1 give ∥u−uh∥DG≤∥u−wh∥DG+∥wh−uh∥DG≤(1+2CB1+Cflux)∥u−wh∥DG,∗. This holds for every wh, so taking the infimum proves both assertions.

5 · Examples, counterexamples and false statements

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