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Strictification of a viscosity test function by a quartic perturbation

Statement

Let U⊆Rm be open, let v:U→R, let ϕ∈C1(U), suppose v−ϕ has a local maximum at z0∈U, and fix r>0 with B‾(z0,r)⊆U and v(z)−ϕ(z)≤v(z0)−ϕ(z0) for every z∈B‾(z0,r). For ε>0 define ϕε(z):=ϕ(z)+ε∣z−z0∣4. Then ϕε∈C1(U) agrees with ϕ to first order at the contact, ϕε(z0)=ϕ(z0),Dϕε(z0)=Dϕ(z0), and v−ϕε has a strict maximum over B‾(z0,r) at z0: v(z)−ϕε(z)<v(z0)−ϕε(z0)for every z∈B‾(z0,r)∖{z0}. The same statement with ϕε:=ϕ−ε∣z−z0∣4 strictifies a local minimum contact of a test function, and the first jet at the contact is again unchanged. No choice principle is used.

Facts & Assumptions

Given: An open U⊆Rm, functions v:U→R and ϕ∈C1(U), a point z0∈U, a radius r>0 with B‾(z0,r)⊆U and v(z)−ϕ(z)≤v(z0)−ϕ(z0) for all z∈B‾(z0,r), and for ε>0 the function ϕε(z)=ϕ(z)+ε∣z−z0∣4.

[F1]

The map q(z):=∣z−z0∣4 is a polynomial in the coordinates of z, hence of class C1 on Rm, with q(z0)=0 and Dq(z0)=0; more precisely Dq(z)=4∣z−z0∣2(z−z0) for every z, the derivative being the total derivative in the sense of The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder and its components the partial derivatives of Directional derivatives and partial derivatives of a map U⊆Rm→Rn.

[F2]

If f,g are C1 on an open set, then so is f+g, with D(f+g)=Df+Dg and (f+g)(z0)=f(z0)+g(z0) (The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder, Directional derivatives and partial derivatives of a map U⊆Rm→Rn).

Proof

technique · an explicit perturbation whose first jet vanishes at the contact
1.1F1F2algebra

Regularity and first jet. The function q(z)=∣z−z0∣4 is a polynomial with q(z0)=0 and Dq(z0)=0 by [F1]; adding it to the C1 function ϕ with coefficient ε>0 gives ϕε∈C1(U) with ϕε(z0)=ϕ(z0)+εq(z0)=ϕ(z0) and Dϕε(z0)=Dϕ(z0)+εDq(z0)=Dϕ(z0) by [F2].

2.1step 1.1algebra

Strict maximum. Let z∈B‾(z0,r) with z≠z0. Then ∣z−z0∣4>0, and the hypothesised maximum inequality gives v(z)−ϕ(z)≤v(z0)−ϕ(z0); subtracting the positive quantity ε∣z−z0∣4 from the left-hand side and using ϕε=ϕ+ε∣⋅−z0∣4 and ϕε(z0)=ϕ(z0), we get v(z)−ϕε(z)≤v(z0)−ϕ(z0)−ε∣z−z0∣4<v(z0)−ϕ(z0)=v(z0)−ϕε(z0). Hence z0 is the strict maximum of v−ϕε over B‾(z0,r).

3.1step 2.1F1F2algebra

Minimum case. If v−ϕ has a local minimum at z0 with v(z)−ϕ(z)≥v(z0)−ϕ(z0) on B‾(z0,r) and ϕε−:=ϕ−ε∣z−z0∣4, the same two computations with signs reversed give ϕε−(z0)=ϕ(z0), Dϕε−(z0)=Dϕ(z0) and v(z)−ϕε−(z)>v(z0)−ϕε−(z0) for every z∈B‾(z0,r)∖{z0}.

4.1step 1.1step 2.1step 3.1∎

Conclusion. Step 1.1 and step 2.1 give the upper-contact statement, and step 3.1 gives the lower-contact statement; the proof used only the polynomial computation [F1] and additivity [F2], so it selects nothing and uses no choice principle.

Remarks

  • Why the quartic. The perturbation has value 0 and gradient 0 at the contact, so it changes neither the value nor the first jet tested in the viscosity inequalities, while it is strictly positive away from the contact and therefore turns a nonstrict contact into a strict one. This is the device that lets the stability and supremum-envelope arguments localise a maximum on a closed ball without losing the tested jet.
  • Scope. The statement is pointwise in the ball and does not require v to be semicontinuous, bounded or measurable; the compactness and extreme-value suppliers For n≥1, every Euclidean closed ball and every Euclidean sphere of positive radius is compact and Semicontinuous extreme value theorem on compact Euclidean sets are available for applications that patch such a ball maximum into a global one, and they are not needed for the computation above.

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