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Failure of the supersolution test for the lower envelope allows a local bump

Statement

Let U⊆Rn+1 be open, let H:U×Rn→R be continuous, and let w:U→R be an upper semicontinuous viscosity subsolution of ut+H(x,t,Du)=0 in U. Suppose the lower semicontinuous envelope w∗ fails the supersolution test at z^∈U in the following precise sense: w∗(z^)∈R and there is ϕ∈C1(U) such that w∗−ϕ has a local minimum at z^ and ϕt(z^)+H(z^,Dϕ(z^))<0. Then for every sufficiently small κ>0 there is a viscosity subsolution Wκ of the same equation in U with Wκ≥w on U,sup⁡U(Wκ−w)>0,Wκ=w on {z∈U:∣z−z^∣≥κ}. Moreover Wκ can be taken to be max⁡(w,χ) on a small ball around z^ and w outside it, where χ is a classical subsolution with χ(z^)=w∗(z^)+δ for some δ>0. No choice principle is used.

Facts & Assumptions

Given: Open U⊆Rn+1, continuous H:U×Rn→R, an upper semicontinuous viscosity subsolution w:U→R, its lower envelope w∗, a point z^∈U with w∗(z^)∈R and a C1 test ϕ with w∗−ϕ having a local minimum at z^ and c:=−(ϕt(z^)+H(z^,Dϕ(z^)))>0.

[F1]

w∗(z)=sup⁡r>0inf⁡{w(y):∣y−z∣≤r} is the lower semicontinuous envelope of w, it satisfies w∗≤w pointwise, and for every η>0 there are points z arbitrarily close to z^ with w(z)<w∗(z^)+η (Upper and lower semicontinuous envelopes by local limsup and liminf).

[F2]

A finite maximum of finitely many viscosity subsolutions of the equation in an open set is a viscosity subsolution (Finite maxima of subsolutions and finite minima of supersolutions); a C1 function with χt+H(z,Dχ)≤0 pointwise is a viscosity subsolution of the same equation (Classical solutions are viscosity solutions and differentiable viscosity solutions solve the equation pointwise, Viscosity subsolutions and supersolutions of a first-order equation and of the Cauchy problem).

[F3]

A continuous function f with f(z^)<0 is negative on a neighbourhood of z^; here the function in question is z↦ϕt(z)+H(z,Dϕ(z)) (The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder, Viscosity subsolutions and supersolutions of a first-order equation and of the Cauchy problem for the smoothness conventions).

Proof

technique · a strict test-function bump plus the finite-maximum rule
1.1F1F2F3algebra

The bump function. Fix κ>0 with B‾(z^,κ)⊆U and choose r∈(0,κ] small. For γ>0 put ϕ~(z):=ϕ(z)−γ∣z−z^∣4, so that ϕ~∈C1(U), ϕ~(z^)=ϕ(z^) and Dϕ~(z^)=Dϕ(z^); shrinking r if necessary and using [F3], we may assume ϕ~t(z)+H(z,Dϕ~(z))≤−c/2<0 for all z∈B‾(z^,r), so every vertical translate of ϕ~ is a classical, hence viscosity, subsolution there. Since w∗−ϕ has a local minimum at z^, after shrinking r we have w∗(z)−ϕ~(z)≥m+γ∣z−z^∣4 for z∈B‾(z^,r), where m:=w∗(z^)−ϕ(z^). Choose 0<δ<γ(r/2)4 and define χ:=ϕ~+m+δ, a classical subsolution on B‾(z^,r) with χ(z^)=w∗(z^)+δ. On the annulus r/2≤∣z−z^∣≤r we have w∗(z)≥ϕ~(z)+m+γ∣z−z^∣4≥χ(z)−δ+γ(r/2)4>χ(z), and since w∗≤w by [F1] this gives χ<w there. By continuity of χ, choose r0∈(0,r/2) so that χ(z)>w∗(z^)+δ/2 whenever ∣z−z^∣<r0. The lower-envelope definition [F1] gives a point z0 in this ball with w(z0)<w∗(z^)+δ/2<χ(z0).

2.1step 1.1F2algebra∎

The bump is a subsolution. Define W:=max⁡(w,χ) on B(z^,r) and W:=w on U∖B(z^,r); this is well defined because on the sphere ∣z−z^∣=r one has χ<w by step 1.1. Then W≥w on U, and sup⁡U(W−w)>0 at the point z0 of step 1.1. On the ball B(z^,r) the function W is the maximum of the viscosity subsolution w and the classical, hence viscosity, subsolution χ, so it is a viscosity subsolution there by [F2]; on the exterior of B‾(z^,r) it equals the subsolution w; and near every point of the sphere it equals w, which is a subsolution, so by locality of the definition W is a viscosity subsolution on all of U. Since χ<w on the annulus, W=w outside B(z^,r)⊆B(z^,κ), that is W=w on {z:∣z−z^∣≥κ}; and W is upper semicontinuous as a maximum of the upper semicontinuous w and the continuous χ.

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