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CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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For n≥1, every Euclidean closed ball and every Euclidean sphere of positive radius is compact

Statement

For n≥1, c∈Rn, and r>0, the Euclidean closed ball B‾2(c,r) and Euclidean sphere S2(c,r) are compact.

Facts & Assumptions

Given: n≥1, c∈Rn, and r>0.

[L1]

The sets B‾2(c,r) and S2(c,r) are respectively the points satisfying ∥x−c∥2≤r and ∥x−c∥2=r (Euclidean spheres and closed balls as subspaces of Rn).

[L2]

The Euclidean norm is continuous and satisfies ∣∥u∥2−∥v∥2∣≤∥u−v∥2 (The finite and reverse triangle inequalities for a norm; and for n≥1 every norm N on Rn satisfies N(x)≤C∥x∥1 and is Lipschitz, hence continuous, for d2).

Proof

technique · direct
1.1

Both sets are bounded: B‾2(c,r) lies in the ball of radius r+1 about c, and S2(c,r)⊆B‾2(c,r).

L1L4
1.2

The complement of B‾2(c,r) is open: if ∥x−c∥2>r, then the ball about x of radius (∥x−c∥2−r)/2 stays in the complement by [L2].

L1L2L4
1.3

The complement of S2(c,r) is open: if ∥x−c∥2≠r, then a ball about x of radius ∣∥x−c∥2−r∣/2 avoids the sphere by [L2].

L1L2L4
2.1

Thus both sets are closed and bounded, hence compact by [L3].

step 1.1step 1.2step 1.3L3∎

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