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Submean inequality for heat subsolutions on heat balls

Statement

Assume Countable Choice. Let u be of class C2,1 on a neighbourhood of the closed heat ball Er(t,x) of Heat balls and their time slices and suppose ut−Δu≤0 there. Then u(x,t)≤12rn∫t−r2/4πtρn(t−s)t−s∫∣y−x∣=ρn(t−s)u(y,s) dS(y) ds. In particular, if u≤M on Er(t,x) then u(x,t)≤M.

Facts & Assumptions

Given: Countable Choice, a C2,1 function u on a neighbourhood of the closed heat ball Er(t,x) with ut−Δu≤0 there.

[A1]

Countable Choice is the ambient hypothesis (The Axiom of Countable Choice (ACω)).

[F1]

On the heat ball below its top point, the defining inequality gives Γ(x−y,t−s)−r−n≥0; the single top point is irrelevant to the volume integral. The slice radius is ρn(τ)=2nτlog⁡r24πτ>0 for 0<τ<r2/(4π) (Heat balls and their time slices).

[F2]

Representation formula: for u of class C2,1 near Er(t,x) and f=ut−Δu, u(x,t)=∬E(Γ(x−y,t−s)−r−n)f(y,s) dy ds+12rn∫t−r2/4πtρn(t−s)t−s∫∣y−x∣=ρn(t−s)u(y,s) dS(y) ds, all integrals absolutely convergent (Heat-ball representation formula).

Proof

Given: Countable Choice, u of class C2,1 near the closed heat ball Er(t,x) with ut−Δu≤0 there, and a constant M with u≤M on Er(t,x).

1.1A1F1F2given

Put f:=ut−Δu; by hypothesis f≤0 on Er(t,x), while [F1] gives Γ(x−y,t−s)−r−n≥0 there, so its integrand is nonpositive almost everywhere and the double integral in the representation formula of [F2] is ≤0.

2.1step 1.1F2given

Applying [F2] and discarding the nonpositive double integral by step 1.1 gives u(x,t)≤12rn∫t−r2/4πtρn(t−s)t−s∫∣y−x∣=ρn(t−s)u(y,s) dS(y) ds, which is the submean inequality.

3.1step 2.1F1F2given∎

If in addition u≤M on Er(t,x), then the averaging kernel ρn(t−s)2rn(t−s) is nonnegative by [F1] and the sphere integrals of the constant M satisfy 12rn∫t−r2/4πtρn(t−s)t−s∫∣y−x∣=ρn(t−s)M dS(y) ds=M, because the representation formula [F2] applied to the constant function u≡M (whose forcing vanishes) reduces to that identity; hence step 2.1 gives u(x,t)≤M.

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