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Strong parabolic maximum principle

Statement

Assume Countable Choice. Let Q=Ω×(0,T] be a parabolic cylinder with Ω bounded, let u∈C2,1(Q‾) satisfy ut−Δu≤0 in Q, and suppose the maximum M:=max⁡Q‾u is attained at a point (x0,t0) with x0∈Ω and 0<t0≤T. Let Ω0 be the connected component of Ω containing x0. Then u=Mon Ω0×(0,t0].

Facts & Assumptions

Given: Countable Choice, a parabolic cylinder Q=Ω×(0,T] with Ω bounded, u∈C2,1(Q‾) with ut−Δu≤0 in Q, and a point (x0,t0) with x0∈Ω, 0<t0≤T and u(x0,t0)=M:=max⁡Q‾u.

[A1]

Countable Choice is the ambient hypothesis (The Axiom of Countable Choice (ACω)).

[F1]

Submean inequality: if u is C2,1 on a neighbourhood of a closed heat ball Eη(P) and ut−Δu≤0 there, then u(P)≤12ηn∫tP−η2/4πtPρn(tP−s)tP−s∫∣y−xP∣=ρn(tP−s)u(y,s) dS(y) ds, and u(P)≤M whenever u≤M on Eη(P) (Submean inequality for heat subsolutions on heat balls).

[F2]

Time slices of heat balls: for 0<τ<r2/(4π) the time slice of Er(t,x) is the closed ball of radius ρn(τ)=2nτlog⁡r24πτ; the slice at τ=r2/(4π) is the single point {x} and the slice is empty for τ>r2/(4π), so Er(t,x)⊆Q forces t−r2/(4π)>0; the spatial projection of Er(t,x) then lies compactly inside the open set Ω (Heat balls and their time slices).

[F3]

The level set Lr(P):={(y,s):s<tP, Γ(xP−y,tP−s)=r−n} is the lateral part of ∂Er(P), it is a C∞ hypersurface on which ∇Γ≠0, and the top point P is the only point of ∂Er(P) outside it (Heat balls and their time slices).

[F4]

Representation formula: for u of class C2,1 near the closed heat ball Er(P), u(P)=∬E(Γ(xP−y,tP−s)−r−n)(ut−Δu)+Λr(P)[u], where Λr(P)[g]:=12rn∫0r2/4πρn(τ)τ∫∣y−xP∣=ρn(τ)g(y,tP−τ) dS(y) dτ for continuous g; applied to the constant function 1, whose forcing vanishes, it gives Λr(P)[1]=1 (Heat-ball representation formula).

[F5]

The lateral functional is a positive measure with density R(τ)n/(2rnτ) in the sphere-time parametrization for 0<τ<r2/(4π), as computed in Heat-ball representation formula. Its total mass is one by [F4]. Every nonempty open piece of this parameter domain has positive measure: for n≥2, a regular sphere chart has strictly positive Gram density, and a small coordinate box has positive Lebesgue measure; for n=1 each of the two sphere points has counting mass one. Thus a continuous nonnegative function with zero lateral integral vanishes on the parametrized part of Lr(P). It also vanishes at the lower tip by continuity, since that tip is a limit of lateral points. The lateral level itself is not compact (it omits the top); no compactness assertion or mass at a tip is needed (Surface integration on compact C1 hypersurfaces, A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included, Monotonicity and nonnegative homogeneity of the nonnegative integral, The nonnegative integral agrees with the simple integral on simple functions).

[F6]

Chaining: for open Ω, times 0<t1<t0≤T<∞ and a Lipschitz path γ:[0,1]→Ω with compact image K, there is ρ>0 with Eρ(P)⊆Ω×(0,T] for every P∈K×[t1,t0], and for every s∈[t1,t0) there is a chain P0=(γ(0),t0),…,PN=(γ(1),s), all lying in K×[t1,t0], with Pj+1∈Eρ(Pj) (Heat-ball chains reach earlier points).

[F7]

Ω0 is open and connected, hence polygonally connected: any two of its points are joined by a polygonal, hence Lipschitz, path with compact image (Every connected component of an open subset of Rn is open and polygonally connected, Separation of a topological space, connected and disconnected spaces, clopen sets, and connected subsets).

Proof

Given: Countable Choice, a bounded parabolic cylinder Q, a subsolution u∈C2,1(Q‾) with maximum M=u(x0,t0) at x0∈Ω, 0<t0≤T.

1.1A1F1F2F3F4F5F8given

Fix P∈Q with u(P)=M and η>0 with Eη(P)⊆Q. Then u=M on the lateral boundary Lη(P). If tP<T, the spatial projection of Eη(P) is compactly contained in Ω and its times lie in [tP−η2/4π,tP] with both endpoints strictly inside (0,T), so u is C2,1 on a neighbourhood of the closed heat ball and [F1] and [F4] apply: M=u(P)≤Λη(P)[u]≤M Λη(P)[1]=M, since u≤M on Q; hence Λη(P)[M−u]=0 and [F5] gives M−u≡0 on Lη(P). If tP=T, put Pδ:=(xP,T−δ) for 0<δ<12(T−η2/4π), so that Eη(Pδ)⊆Ω×(0,T) and u is C2,1 on a neighbourhood of it; substituting s′=s−δ in the slice formula of [F1] turns Λη(Pδ)[u] into Λη(P)[u(⋅,⋅−δ)], so u(Pδ)≤Λη(P)[u(⋅,⋅−δ)]≤M by [F1] and [F4]; as δ↓0 one has u(Pδ)→u(P)=M, while sup⁡Lη(P)∣u(y,s−δ)−u(y,s)∣→0 by [F8] because all the points (y,s−δ) and (y,s) lie in the compact Q‾; therefore M≤Λη(P)[u]≤M and again Λη(P)[M−u]=0, so [F5] gives M−u≡0 on Lη(P).

2.1step 1.1F2F3given

If P∈Q has u(P)=M and Eη(P)⊆Q, then Eη(P)⊆S:={R∈Q:u(R)=M}: the top point P lies in S, and for Q∗∈Eη(P) with Q∗≠P put η∗:=Γ(xP−y∗,tP−s∗)−1/n, which is well defined and positive because s∗<tP; then η∗≤η, so Eη∗(P)⊆Eη(P)⊆Q and Q∗∈Lη∗(P), and step 1.1 applied with radius η∗ gives u(Q∗)=M.

3.1step 2.1F6F7given

Fix y∈Ω0 and s∈(0,t0). By [F7] choose a polygonal, hence Lipschitz, path γ:[0,1]→Ω0 from x0 to y, with compact image K, and put t1:=s/2, so that 0<t1<t0≤T and s∈[t1,t0). By [F6] there are ρ>0 with Eρ(R)⊆Q for every R∈K×[t1,t0], and a chain P0=(x0,t0),P1,…,PN=(y,s) inside K×[t1,t0] with Pj+1∈Eρ(Pj) for all j<N. Since u(x0,t0)=M, induction on j using step 2.1 gives Pj∈S for every j, and in particular u(y,s)=M.

4.1step 3.1given∎

Since y∈Ω0 and s∈(0,t0) were arbitrary, step 3.1 gives u=M on Ω0×(0,t0), and continuity of u on Q‾ extends this to the closed time level Ω0×(0,t0], which is the claim. The only selections made are finitely many real parameters and one integer N; Countable Choice is used only through the measure, integration and compactness suppliers named in [F1]–[F8].

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