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Zeta logarithmic derivative zero bound
Statement
Write and let range over nontrivial zeta zeros with multiplicity. With the Hadamard constant , This is a meromorphic identity, using convergent genus-one terms. Uniformly for , and , and this real series is absolutely convergent.
Facts & Assumptions
Given: The data and hypotheses of the statement.
The Riemann xi function has its genus-one Hadamard product over the nontrivial zeros of zeta: There exist constants such that where the product runs over the nontrivial zeros of , counted with multiplicity, and The product converges in the genus-one canonical sense.
The Riemann xi function : The completed function extends meromorphically with simple poles at and by thm-completed-riemann-zeta-functional-equation. The Riemann xi function is defined on by The role of the factor is to cancel the two simple poles of the completed function . Thus is the entire completion, while remains meromorphic.
Stirling's formula for Gamma: Fix with . On the closed sector , using the principal logarithm in , one has as .
All higher complex derivatives exist and satisfy Cauchy's integral formula on an interior circle: Let be holomorphic on , let , and let for . Define and, whenever it exists, . Then every exists on and, for every and , In particular, every holomorphic function has complex derivatives of all orders locally.
A unit-interval bound for zeta zeros: The number of nontrivial zeta zeros, with multiplicity, whose ordinates lie in is for .
The only zeros of zeta on the nonpositive real axis are the negative even integers, and every other zero lies in the open critical strip: For each integer , These are the only zeros of on the nonpositive real axis. Every other zero of satisfies . Moreover, if is a nontrivial zero, then so are and .
Proof
For bounded away from zeros, the terms are . The unit-interval count, reflected using conjugate zeros, makes their tails normally convergent. Logarithmically differentiating the canonical product therefore gives .
Put . In a wider fixed sector containing these high-height points, Stirling gives with . On discs of radius in that sector, Cauchy gives . Thus , whose real part is . Remaining bounded heights are compact.
In the defining formula for , use to write . The Gamma recurrence follows by integration by parts on its defining integral and meromorphic continuation. Differentiating this equality proves the first formula wherever its factors are nonzero, hence meromorphically.
For fixed the real summands have tails , since . The same estimate applies to . Their absolute convergence follows from the unit-band count. Absorb the constant and the bounded pole term into , obtaining the second formula.
Depends on
- The Riemann xi function has its genus-one Hadamard product over the nontrivial zeros of zeta
- The Riemann xi function $\xi(s)=\tfrac12 s(s-1)\Lambda(s)$
- Stirling's formula for Gamma
- All higher complex derivatives exist and satisfy Cauchy's integral formula on an interior circle
- A unit-interval bound for zeta zeros
- The only zeros of zeta on the nonpositive real axis are the negative even integers, and every other zero lies in the open critical strip
Used by
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Sources
- §8.3, Hadamard calculation in proof of Theorem 8.8 (standard reference, not scraped)