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Explicit de rham mayer vietoris connecting class

Statement

Under countable choice, let δ be the Mayer–Vietoris connecting homomorphism obtained from the short exact cochain sequence in F3 by reindexing Cn=Cn and using the connector convention in F4. For a closed k-form ω on UV, δ[ω]=[η], where ηU=d(ρVω) and ηV=d(ρUω), with products smoothly extended by zero as in the lift construction. This class is independent of partition, lift and representative.

Facts & Assumptions

Given: Assume countable choice. A closed overlap form ω and the partition lift (α,β)=(ρVω,ρUω).

[F1]

Mayer vietoris sequence in de rham cohomology: Under countable choice the de Rham Mayer–Vietoris sequence is exact: Hk(M)rHk(U)Hk(V)sHk(UV)δHk+1(M), beginning with 0H0(M). Its proof obtains this δ by applying the long exact sequence theorem to the short exact de Rham cochain sequence in F3, with no additional differential sign.

[F2]

The de rham mayer vietoris difference map is surjective: Assume countable choice. The difference map s:Ωk(U)Ωk(V)Ωk(UV) is surjective in every degree.

[F3]

Short exact mayer vietoris sequence of de rham complexes: Under countable choice, 0Ω(M)rΩ(U)Ω(V)sΩ(UV)0 is short exact as a sequence of real cochain complexes, with s(α,β)=βα.

[F4]

Elementwise formula for the connecting map in module categories: Let R be a ring and let 0AiBpC0 be a short exact sequence of chain complexes of left R-modules. If [c]Hn(C) is represented by a cycle cCn, choose a lift bBn with pn(b)=c, and let aAn1 be the unique element satisfying in1(a)=dnB(b). Then n([c])=[a]Hn1(A). This class is independent of the chosen lift b and of the chosen cycle representative c.

Proof

technique · direct
1.1

On the overlap, dβdα=d(βα)=dω=0. Thus the two smooth forms dα,dβ glue to η. On each open dη=d2α or d2β, hence is zero. The graded product rule also gives ηUV=dρUω=dρVω, fixing the sign.

F2F3given
2.1

Reindex the short exact sequence F3 as chain complexes with Cn=Cn. By F1 its connecting homomorphism is the displayed δ, with no added sign. The lift (α,β) in degree k has differential rη in degree k1, so F4 gives δ[ω]=[η] in Hk+1(M). Its independence of lift and cycle representative applies over the ring R; any other partition supplies another lift, so partition independence follows too.

F1F3F4step 1.1

Source locator

Lee, Theorem 17.20, pp.449–450, and its full proof pp.462–463. This page reverses Lee’s difference convention consistently: s(α,β)=βα.

Depends on

Used by

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Sources