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Finite biproducts of complexes are computed degreewise
Statement
Let be an abelian category. Finite biproducts in are formed degreewise. In particular, for every .
Facts & Assumptions
Given: An abelian category and chain complexes and in .
is additive, so it has finite biproducts (The category of complexes in an additive category is additive).
Homology is an additive functor (Homology is an additive functor).
Proof
The proof of [L1] constructs the biproduct degreewise, with term and differential . Thus finite biproducts of complexes are formed degreewise.
Since is additive by [L2], it preserves finite biproducts. Applying it to the biproduct from step 1.1 gives
Depends on
Used by
- The cone of the zero map is the direct sum with a shift Proposition
- The full subcategory of acyclic complexes is thick in the homotopy category Proposition
- The quotient of the mapping cylinder by its source is the mapping cone Proposition
- The canonical mapping-cone sequence is degreewise split short exact Theorem
- The homotopy category is additive Theorem
- The mapping cylinder factors a chain map Theorem
Dependency tree · two levels
10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Charles A. Weibel, Chapter 1 of An Introduction to Homological Algebra (standard reference, not scraped)