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Highest weight of the dual representation

Statement

Assume the Axiom of Choice. Let g be a finite-dimensional complex semisimple Lie algebra with Cartan subalgebra h and a fixed positive system, let λ be dominant integral, let V(λ)=L(λ) be the finite-dimensional irreducible module of highest weight λ, and let w0 be the longest element of the Weyl group (Length and longest Weyl-group element). Then the dual module V(λ)∗ (Direct-sum, dual, Hom, and tensor representations) is irreducible and has highest weight −w0(λ).

Facts & Assumptions

Given: The Axiom of Choice, such g,h, a fixed positive system, a dominant integral λ, the module V(λ) and the longest Weyl element w0.

[A1]

The Axiom of Choice is assumed; it enters through the root-space theory used by the cited suppliers (The Axiom of Choice).

[L1]

The dual space V(λ)∗ carries the representation (x⋅φ)(v)=−φ(x⋅v), and the weight spaces satisfy dim⁡(V(λ)∗)−μ=dim⁡V(λ)μ (Direct-sum, dual, Hom, and tensor representations, Weight and weight space).

[L2]

V(λ)=L(λ) is a nonzero finite-dimensional irreducible highest weight module of highest weight λ, generated by its highest weight vector vλ, and all its weights ν satisfy ν≤λ with V(λ)λ=Cvλ (Highest-weight classification, An irreducible module is generated by its highest-weight vector, Highest weight modules lie below the top weight, The highest-weight space is one-dimensional).

[L3]

Weight multiplicities of a finite-dimensional module are invariant under the Weyl group: dim⁡V(λ)wν=dim⁡V(λ)ν for every w∈W, and the set of weights is W-invariant (Simple reflections preserve weight multiplicities).

[L4]

The longest element w0 exists, is unique, and satisfies w0(Φ+)=Φ−; the Weyl group acts on E by linear maps (Weyl length equals inversion number, Length and longest Weyl-group element, Weyl group).

[L5]

The root order is a partial order defined by μ≤ν  ⟺  ν−μ∈Q+, and ν∈Q+ is a nonnegative integral combination of the simple roots; w0 maps the set of nonnegative integral combinations of the simple roots onto the set of nonpositive ones (Root order on weights, Simple roots form a signed integral basis, [L4]).

[L6]

The zero module is not irreducible; a nonzero submodule of an irreducible module is the whole module (Irreducible, completely reducible, and faithful representations).

Proof

technique · direct
1.1A1L1

By [L1] V(λ)∗ is a finite-dimensional g-module with dim⁡(V(λ)∗)μ=dim⁡V(λ)−μ for every μ.

1.2L2L3L4L5

First we show that w0(λ) is the minimum of the weights of V(λ): it is a weight because λ is one and the weight set is W-invariant by [L3]; and for any weight ν of V(λ) the vector w0−1(ν) is a weight, hence λ−w0−1(ν)∈Q+ by [L2], and applying w0 gives w0(λ)−ν∈w0(Q+)=−Q+ by [L4] and [L5]; thus ν−w0(λ)∈Q+, that is, w0(λ)≤ν.

2.1step 1.1step 1.2

Consequently the weights of V(λ)∗ are the negatives of the weights of V(λ) by step 1.1, so the maximum weight of V(λ)∗ is −w0(λ), and it is a weight of V(λ)∗ because w0(λ) is a weight of V(λ).

2.2L2L6step 1.1

The module V(λ)∗ is irreducible: if 0≠W⊊V(λ)∗ is a proper submodule, its annihilator W⊥={v∈V(λ):φ(v)=0 for all φ∈W} is a submodule of V(λ), because for φ∈W and v∈W⊥ the dual action gives φ(x⋅v)=−(x⋅φ)(v)=0 since x⋅φ∈W; since W≠V(λ)∗ we have dim⁡W⊥=dim⁡V(λ)−dim⁡W>0, so W⊥=V(λ) by irreducibility of V(λ) from [L2], and hence W=0; thus the only nonzero submodule is the whole space.

3.1L2L3step 1.1step 2.1

The multiplicity of the weight −w0(λ) in V(λ)∗ is dim⁡V(λ)w0(λ)=dim⁡V(λ)λ=1 by steps 1.1, [L3] and [L2].

4.1L2step 2.1step 3.1step 2.2

By step 2.2 the module V(λ)∗ is finite dimensional and irreducible, with unique maximal weight −w0(λ) by steps 2.2 and 3.1; by the classification theorem [L2] its highest weight is −w0(λ).

5.1step 4.1∎

Therefore V(λ)∗ is irreducible of highest weight −w0(λ), as asserted.

Depends on

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