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PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-09-01
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Two tubular neighbourhood germs are isomorphic near the zero section

Statement

Let Φ1:Ω1→M and Φ2:Ω2→M be two tubular neighbourhoods of the same closed embedded submanifold S⊆M built on the same normal bundle ν(S). Then, after shrinking Ω1 and Ω2 around the zero section, there is a diffeomorphism Ψ:Ω1′→Ω2′ such that Φ2∘Ψ=Φ1 and Ψ restricts to the identity on the zero section.

Facts & Assumptions

Given: Two tubular neighbourhood charts Φ1:Ω1→M and Φ2:Ω2→M for the same closed embedded submanifold S⊆M.

[F1]

A tubular neighbourhood chart is a diffeomorphism from an open normal-bundle neighbourhood of the zero section onto an ambient open neighbourhood of S (Tubular neighbourhoods of embedded submanifolds).

[L1]

Tubular neighbourhoods exist in smooth ambient manifolds (The tubular neighbourhood theorem in a smooth ambient manifold).

Proof

technique · direct
1.1F1givenconstruct

By [F1], both Φ1 and Φ2 are diffeomorphisms onto open neighbourhoods of S. Shrink the domains so that their images lie in the common overlap. Then Ψ:=Φ2−1∘Φ1 is a diffeomorphism between the shrunken domains.

2.1F1step 1.1

On the zero section both tubular charts agree with the inclusion of S into M, so Ψ(p,0)=(p,0) for every p∈S. Thus Ψ restricts to the identity on the zero section.

3.1L1step 1.1step 2.1∎

The relation Φ2∘Ψ=Φ1 is built into the definition of Ψ, and [L1] guarantees that these tubular charts are honest smooth objects rather than formal placeholders. Hence the two tubular neighbourhoods define the same germ near the zero section.

Depends on

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Dependency tree · two levels

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Sources