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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-08-31
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A bounded above acyclic complex of injective objects is contractible when its cycle monomorphisms split

Statement

Let C∙ be a bounded-above acyclic chain complex of injective objects in an abelian category. If every cycle inclusion in:Zn(C)↪Cn admits a retraction rn:Cn→Zn(C), then C∙ is contractible.

Facts & Assumptions

Given: A bounded-above acyclic complex C∙ and retractions rn:Cn→Zn(C) with rnin=1.

[L1]

Boundaries and cycles are defined degreewise in a chain complex (Cycle and boundary subobjects of a complex).

[L2]

Acyclic means exact at every degree (Exactness of a complex at a degree and acyclic complexes).

[L3]

The previous theorem treats the dual split criterion on the epimorphism side (A bounded below acyclic complex of projective objects is contractible when its cycle epimorphisms split).

[L4]

The stated proof uses the chosen retractions. Injectivity of the terms Cn alone does not provide retractions onto Zn(C); the extension property in Injective object would provide such a retraction if the target Zn(C) were injective.

[L5]

Opposite abelian categories are abelian (The opposite of an abelian category is abelian).

Proof

technique · direct
1.1L1L2givenalgebra

Because in splits, each exact sequence 0→Zn(C)→inCn→Zn−1(C)→0 decomposes Cn as Cn≅Zn(C)⊕Zn−1(C), with the differential again equal to projection onto the second factor followed by inclusion into Cn−1.

2.1L3L4L5step 1.1algebra∎

Step 1.1 is the same compatible splitting pattern used in [L3], so the same contraction argument applies and C∙ is contractible. The proof depends on the assumed retractions, as [L4] emphasizes; [L5] explains the formal duality with the epimorphism-side criterion.

Depends on

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Sources