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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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A bounded below acyclic complex of projective objects is contractible when its cycle epimorphisms split

Statement

Let C be a bounded-below acyclic chain complex of projective objects in an abelian category. For each n, let πn:CnZn1(C) be the canonical epimorphism characterized by dn=in1πn, where in1:Zn1(C)Cn1 is the cycle inclusion. If every πn admits a section σn, then C is contractible.

Facts & Assumptions

Given: A bounded-below acyclic complex C and splittings σn:Zn1(C)Cn with πnσn=1.

[L1]

Boundaries and cycles are the image of dn+1 and kernel of dn (Cycle and boundary subobjects of a complex).

[L2]

Acyclic means exact at every degree, so Bn1(C)=Zn1(C) (Exactness of a complex at a degree and acyclic complexes).

[L3]

A bounded-below complex has only finitely many nonzero terms below each degree (Bounded, bounded below, and bounded above complexes).

[L4]

The split-exact criterion of the previous lemma yields contractibility (A degreewise split exact complex with compatible splittings is contractible).

[L5]

The stated proof uses the chosen sections. Projectivity of the terms Cn alone does not provide sections of CnZn1(C); the lifting property in Projective object would provide such a section if the target Zn1(C) were projective.

Proof

technique · direct
1.1

By [L2], each short exact sequence 0Zn(C)CnπnZn1(C)0 is exact, and the section σn splits it. Therefore CnZn(C)Zn1(C) for every n, with differential equal to projection onto the second summand followed by the cycle inclusion.

L1L2givenalgebra
2.1

Step 1.1 is exactly the compatible decomposition required by [L4], so C is contractible. As [L5] emphasizes, the contraction comes from the chosen sections rather than from projectivity of the terms alone.

L3L4L5step 1.1algebra

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