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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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A bounded below acyclic complex of projective objects is contractible when its cycle epimorphisms split

Statement

Let C∙ be a bounded-below acyclic chain complex of projective objects in an abelian category. For each n, let πn:Cn→Zn−1(C) be the canonical epimorphism characterized by dn=in−1πn, where in−1:Zn−1(C)↪Cn−1 is the cycle inclusion. If every πn admits a section σn, then C∙ is contractible.

Facts & Assumptions

Given: A bounded-below acyclic complex C∙ and splittings σn:Zn−1(C)→Cn with πnσn=1.

[L1]

Boundaries and cycles are the image of dn+1 and kernel of dn (Cycle and boundary subobjects of a complex).

[L2]

Acyclic means exact at every degree, so Bn−1(C)=Zn−1(C) (Exactness of a complex at a degree and acyclic complexes).

[L3]

A bounded-below complex has only finitely many nonzero terms below each degree (Bounded, bounded below, and bounded above complexes).

[L4]

The split-exact criterion of the previous lemma yields contractibility (A degreewise split exact complex with compatible splittings is contractible).

[L5]

The stated proof uses the chosen sections. Projectivity of the terms Cn alone does not provide sections of Cn↠Zn−1(C); the lifting property in Projective object would provide such a section if the target Zn−1(C) were projective.

Proof

technique · direct
1.1L1L2givenalgebra

By [L2], each short exact sequence 0→Zn(C)→Cn→πnZn−1(C)→0 is exact, and the section σn splits it. Therefore Cn≅Zn(C)⊕Zn−1(C) for every n, with differential equal to projection onto the second summand followed by the cycle inclusion.

2.1L3L4L5step 1.1algebra∎

Step 1.1 is exactly the compatible decomposition required by [L4], so C∙ is contractible. As [L5] emphasizes, the contraction comes from the chosen sections rather than from projectivity of the terms alone.

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