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Assouad lower bound for a squared-error hypercube
Statement
Let , , and consider the finite experiment indexed by with sample laws . The target is , the action is in , and loss is squared Euclidean distance. For each coordinate , let denote the vector with bit flipped, and set For every randomized estimator kernel , and the same lower bound holds for the minimax risk. The total variation convention is .
Facts & Assumptions
Given: A positive integer , a number , the finite hypercube experiment, and an arbitrary randomized action kernel .
Statistical experiments and Parameter-measurable statistical models as kernels: the parameter set is finite with its power-set sigma-algebra and the model assigns to .
Randomized procedures as probability kernels: action-event probabilities are measurable, and each is a probability measure.
Loss functions and risk: the squared-error risk is the nonnegative kernel integral .
Total variation distance for probability laws: total variation is the event supremum and lies in .
Bayes risk and minimax risk: minimax risk is the infimum over procedures of the supremum of their risks.
Proof
For each coordinate , define . This is a measurable -valued function by [F2]. If the true bit is , an action counted by has coordinate squared error at least ; if the true bit is , an action outside that event has coordinate squared error at least . Thus where .
For any two probability laws and measurable , the finite approximants satisfy . By [F4], , and the replacement error is at most . Letting gives . Applying the same result to gives For each coordinate, pair every hypercube vertex with bit to the unique neighbor with bit . There are such pairs, and each pair's two testing errors in step 1.1 sum to at least . Averaging over all vertices therefore gives average coordinate error at least . This establishes the coordinate error bound.
Average the risk bound in step 1.1 over the vertices. Step 2.1 shows that the average risk is at least . The supremum of finitely many risks is at least their arithmetic mean, so every has maximum risk at least this amount. Taking the infimum over procedures using [F5] proves the minimax bound.
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Sources
- John Duchi, Lecture Notes on Statistics and Information Theory, Chapter 8, §§8.5.1–8.5.3 and §8.8.3 (standard reference, not scraped)