Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generated
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Under choice, a space is metrizable if and only if it is regular, T1, and has a σ-discrete basis

Statement

Assume the Axiom of Choice. A space is metrizable if and only if it is regular, T1, and has a σ-discrete basis.

Facts & Assumptions

Given: The Axiom of Choice (The Axiom of Choice) and a topological space X.

[L1]

Under choice every metric space has a σ-discrete open basis, by the closed-core and open-neighborhood construction of Under choice, metric spaces have sigma-discrete open bases.

[L2]

Proof

technique · cases
1.1assume-case forwardL1

If X is metrizable, [L1] gives a σ-discrete basis; metric spaces are regular and T1: singleton complements are open, and for a point x outside a closed set F, a ball B(x,r) missing F has the closure of B(x,r/2) still missing F, by the triangle inequality (Metric space: d(x,y)=0 iff x=y, symmetry, and the triangle inequality; pseudometric and ultrametric).

1.2assume-case reverseL2

If X is regular, T1, and has a σ-discrete basis, [L2] converts that basis to a σ-locally-finite one and then gives a metric.

2.1step 1.1step 1.2cases-exhaustive∎

The cases establish both directions.

Depends on

Used by

Dependency tree · two levels

27 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources