Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-29
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The class-function inner product ⟨χV,χW⟩ equals dim⁡Hom⁡G(W,V)

Statement

Let G be a finite group and let V and W be finite-dimensional complex representations of G with characters χV and χW. Then

⟨χV,χW⟩=dim⁡Hom⁡G(W,V).

Facts & Assumptions

Given: Finite-dimensional complex representations V and W of a finite group G, with characters χV and χW.

[F1]

The inner product of class functions is ⟨φ,ψ⟩=1∣G∣∑g∈Gφ(g)ψ(g)‾ (The standard inner product on cf(G)).

[F2]

For a finite-dimensional complex representation U, the averaging operator PU=1∣G∣∑gρU(g) has image UG and trace dim⁡UG (The averaging operator projects onto the fixed subspace).

[F3]

The fixed points of the diagonal representation on W∗⊗V are exactly the intertwiners W→V, so (W∗⊗V)G≅Hom⁡G(W,V) (For finite-dimensional complex V, the intertwiners V→W are exactly the fixed points of V∗⊗W).

[F4]

Characters add on direct sums, multiply on tensor products, and conjugate on duals (Characters add on direct sums, multiply on tensor products, and conjugate on duals).

[F5]

Trace is linear on finite square matrices (Trace is a linear functional on Mn(F)).

[A1]

The character of a representation is by definition the trace of its action operator, χU(g)=tr⁡ρU(g).

Proof

technique · direct
1.1F2F3given

By [F3], dim⁡Hom⁡G(W,V)=dim⁡(W∗⊗V)G. By [F2] applied to U=W∗⊗V, this equals tr⁡PU for the averaging operator PU=1∣G∣∑gρW∗⊗V(g).

1.2F5A1given

By [F5], tr⁡PU=1∣G∣∑gtr⁡ρW∗⊗V(g)=1∣G∣∑gχW∗⊗V(g), the second equality by [A1].

1.3F4given

By [F4], the tensor-product and dual clauses give χW∗⊗V(g)=χW∗(g)χV(g)=χW(g)‾χV(g).

2.1F1step 1.1step 1.2step 1.3algebra∎

Combining steps 1.1 through 1.3, dim⁡Hom⁡G(W,V)=1∣G∣∑gχW(g)‾χV(g)=1∣G∣∑gχV(g)χW(g)‾, reordering the product of two complex numbers in each summand. This is ⟨χV,χW⟩ by [F1].

Depends on

Used by

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Sources