Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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Complementation preserves hereditary classes and complements their minimal forbidden bases

Statement

If C\mathcal C is hereditary, then C\overline{\mathcal C} is hereditary and

B(C)={H:HB(C)}\mathcal B(\overline{\mathcal C})=\{\overline H:H\in\mathcal B(\mathcal C)\}

up to isomorphism.

Facts & Assumptions

Given: A hereditary graph class C\mathcal C.

[F1]

GCG\in\overline{\mathcal C} exactly when GC\overline G\in\mathcal C (The complement of a graph class).

[L1]

Complementation commutes with taking induced subgraphs (G[W]=G[W]\overline{G[W]}=\overline G[W] for every vertex set WW).

[F2]

A minimal forbidden graph lies outside the class while all its proper induced subgraphs lie inside (Minimal forbidden induced subgraphs and forbidden bases).

[L2]

A hereditary class is determined by its unique minimal forbidden basis (Every hereditary graph class is determined by its unique minimal forbidden induced subgraphs).

Proof

technique · direct
1.1

Let GCG\in\overline{\mathcal C} and WV(G)W\subseteq V(G). Then GC\overline G\in\mathcal C, so G[W]C\overline G[W]\in\mathcal C by heredity.

F1
1.2

Let HB(C)H\in\mathcal B(\mathcal C). Then HC\overline H\notin\overline{\mathcal C}, while for every proper WV(H)W\subsetneq V(H), H[W]CH[W]\in\mathcal C and therefore H[W]=H[W]C\overline H[W]=\overline{H[W]}\in\overline{\mathcal C}.

F1F2L1
2.1

Since G[W]=G[W]\overline{G[W]}=\overline G[W], one has G[W]CG[W]\in\overline{\mathcal C}. Isomorphism closure is likewise preserved, so C\overline{\mathcal C} is hereditary.

step 1.1L1F1
2.2

Hence HB(C)\overline H\in\mathcal B(\overline{\mathcal C}). Applying the same argument to the involution of complementation gives the reverse inclusion.

step 1.2F2
3.1

Therefore the minimal bases are complementary as claimed.

step 2.2L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 32 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources