Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Complementary hereditary classes have complementary forbidden bases

Statement

The class of edgeless graphs is complementary to the class of complete graphs, and their minimal forbidden bases {K2}\{K_2\} and {K2}\{\overline K_2\} are complementary.

Facts & Assumptions

Given: The classes K\mathcal K of complete graphs and E\mathcal E of edgeless graphs.

[L1]

B(K)={K2}\mathcal B(\mathcal K)=\{\overline K_2\} (Complete graphs form the hereditary class with forbidden basis {K2}\{\overline K_2\}).

[L2]

B(E)={K2}\mathcal B(\mathcal E)=\{K_2\} (Edgeless graphs form the hereditary class with forbidden basis {K2}\{K_2\}).

[L3]

Complementation complements the minimal basis of a hereditary class (Complementation preserves hereditary classes and complements their minimal forbidden bases).

[F1]

A graph belongs to the complement class of K\mathcal K exactly when its complement belongs to K\mathcal K.

Verification

technique · direct
1.1

Complementing a complete graph gives an edgeless graph and vice versa, so E=K\mathcal E=\overline{\mathcal K}.

F1
1.2

The two basis graphs satisfy K2=K2\overline{\overline K_2}=K_2.

L1L2
2.1

Thus the displayed bases are complementary, exactly as the general theorem predicts.

step 1.1step 1.2L3

Remarks

K22B(K)complementK22B(E)

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 21 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources