Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-10
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Conditional fatou and dominated convergence

Statement

Assume AC. For nonnegative measurable Xn, E[lim infnXnG]lim infnE[XnG] almost surely, in the extended sense. If real-valued measurable Xn and X satisfy XnX almost surely and XnW almost surely for one nonnegative WL1(P), then E[XnG]E[XG] almost surely and in L1.

Facts & Assumptions

Given: AC and nonnegative measurable Xn; separately real-valued measurable Xn and X such that XnX almost surely and XnW for one nonnegative integrable W.

[F1]

Extended conditional expectation preserves order and increasing limits. (Conditional monotone convergence)

[F2]

Integrable conditional expectation is linear and satisfies the modulus bound. (Basic algebra and order properties of conditional expectation)

[F3]

A common integrable dominator and almost-sure convergence give integrability and L1 convergence. (Dominated convergence)

[F4]

Under AC integrable conditional classes and their versions exist. (Conditional expectation as an ae class)

[F5]

Countable infima and liminf of measurable functions are measurable. (Sequential suprema, infima, limsup, liminf, and pointwise limits of measurable functions are measurable)

Proof

technique · direct
1.1

Put Zn=infknXk. These are measurable by [F5], nonnegative, and increase to lim infkXk. For each kn, [F1] gives E[ZnG]E[XkG] almost surely. There are only countably many pairs (n,k); after removing their null union, take the infimum over kn and then the increasing limit in n. Conditional MCT gives exactly the claimed Fatou inequality.

F1F5
2.1

In the dominated case, XW almost surely, so [F3] gives XL1. Set T=E[WG], Un=E[XnG] and U=E[XG]. These are finite almost surely. Apply step 1.1 to W+Xn and WXn, which are nonnegative. By linearity this gives T+UT+lim infUn and TUTlim supUn. The modulus bound gives Un,UT outside one common null set. Subtracting the finite T yields Ulim infUnlim supUnU, hence almost-sure convergence.

step 1.1F2F3F4
3.1

The differences UnU tend to zero almost surely and are bounded by 2T, with ET=EW<. Ordinary DCT therefore gives EUnU0, the claimed L1 convergence.

step 2.1F2F3

Source notes

Van der Vaart Lemma 1.10(ii)–(iii), printed p.4, full statements read; ordinary MCT, conditional order and the two nonnegative dominated sequences supply the proof here.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

27 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources