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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
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Rotation law for the surface connection form

Statement

Let (M,g) be an oriented Riemannian surface and U⊆M open with specified smooth positively oriented g-orthonormal frames (E1,E2) and (E1′,E2′), with connection forms ω and ω′ in the convention ω(X)=g(∇XE1,E2). On each open patch V⊆U where a smooth angle lift φ:V→R is supplied with E1′=cos⁡φ E1+sin⁡φ E2,E2′=−sin⁡φ E1+cos⁡φ E2, the forms satisfy ω′∣V=ω∣V+dφ, where dφ(X)=X(φ). Any two such lifts of the same frame rotation differ by a locally constant element of 2πZ, so their differentials agree on overlaps; no global angle lift is asserted.

Facts & Assumptions

Given: An oriented Riemannian surface with two specified positive orthonormal frames on an open set U, and an open patch V⊆U carrying a smooth real function φ that expresses the rotation from the first frame to the second.

[F1]

The connection forms of the two frames are defined by ω(Y)=g(∇YE1,E2) and ω′(Y)=g(∇YE1′,E2′), and the frame equations ∇YE1=ω(Y)E2 and ∇YE2=−ω(Y)E1 hold (Connection one-form of an oriented orthonormal frame).

[F2]

For a smooth function f on a manifold, df(X)=Xf for every smooth vector field X (The exterior derivative of a function is its differential).

Proof

technique · Differentiate the rotated frame vector with the product rule and read off the defining inner product
1.1F1givenalgebra

Fix a smooth vector field X on V. Expanding E1′=cos⁡φ E1+sin⁡φ E2 and differentiating with the product rule, the frame equations of [F1] give ∇XE1′=−sin⁡φ (Xφ)E1+cos⁡φ ω(X)E2+cos⁡φ (Xφ)E2−sin⁡φ ω(X)E1=(ω(X)+Xφ)E2′.

2.1F1step 1.1algebra

Since (E1′,E2′) is a g-orthonormal frame, g(E2′,E2′)=1; substituting the expansion of step 1.1 into the definition ω′(X)=g(∇XE1′,E2′) from [F1] yields ω′(X)=ω(X)+Xφ for every smooth X on V.

3.1F2step 2.1

By [F2] applied to the smooth function φ on V, the one-form dφ satisfies dφ(X)=Xφ; hence step 2.1 states the identity of one-forms ω′∣V=ω∣V+dφ on V.

4.1givenstep 2.1step 3.1algebra

Let φ~ be a second smooth angle lift of the same rotation on a connected open set W⊆V. Expanding both expressions for E1′ in the basis (E1,E2) gives cos⁡φ~=cos⁡φ and sin⁡φ~=sin⁡φ; hence φ~−φ takes values in 2πZ, and by continuity it is constant on W, so dφ~=dφ on W. If W is empty the identity is vacuous, and if φ is constant then dφ=0, so ω′∣V=ω∣V there.

5.1step 3.1step 4.1∎

Steps 3.1 and 4.1 prove the stated identity on every supplied patch V and its independence of the choice of lift on overlaps; no global angle lift is constructed or required.

Source locator

Lee, Riemannian Manifolds: An Introduction to Curvature, Chapter 9, §“The Gauss–Bonnet Formula,” printed p. 165, equations (9.4), records the frame equations in the opposite sign convention ωstd=−ω; Datar, Lectures on Riemannian Geometry, Lecture 2, §2.1, printed p. 11, records the same frame equations. The rotation identity is derived above from those frame equations in the present sign convention; the sources are not claimed to state the identity in this sign.

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