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The continuation count is a chain map

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let (fs,gs) be a regular continuation datum from (f−,g−) to (f+,g+) on a closed manifold M, let Φ be its continuation map (The continuation chain map) and let ∂± be the Morse differentials over Λ=Z/2 and Λ=Z (The mod-two Morse differential, The signed Morse differential over the integers).

Then Φ is a chain map: Φk−1∘∂k−=∂k+∘Φkfor every k, in both coefficient cases, with any chosen positive rays in the critical orientation lines in the integral case. Consequently Φ induces a homomorphism [Φ]:HMk(f−,g−;Λ)→HMk(f+,g+;Λ) on Morse homology (Morse homology of a Morse--Smale pair, Chain complex in an abelian category, A graded morphism of chain complexes).

Facts & Assumptions

Given: The Axiom of Choice, a regular continuation datum (fs,gs) with continuation map Φ, and the two Morse differentials.

[F1]

For critical points with index drop one the compactification is a compact one-manifold with boundary, whose boundary is the disjoint union of the once-broken products M−(p,a)×C(a,q) and C(p,b)×M+(b,q) with the prescribed index conditions, and each end moduli space occurring is finite (Continuation trajectories are compact up to breaking, Gluing continuation solutions gives collar neighbourhoods of the broken ends).

[F2]

A compact one-manifold has an even number of boundary points (Boundary of a compact 1-manifold has even cardinality), and a compact oriented one-manifold has signed boundary count zero (Oriented boundary counts of a compact oriented 1-manifold cancel).

[F3]

With the orientation conventions of Orientation lines orient the continuation moduli spaces compatibly with gluing, the sign of a once-broken boundary point of the type (γ−,v) is τ(γ−)τ(v) and the sign of one of the type (v,γ+) is −τ(v)τ(γ+), the relative sign being the ordered fixed-anchor endpoint comparison; the differential conventions of The signed Morse differential over the integers are then such that the signed boundary sum of the boundary points of C‾(p,q) is the coefficient of q in (Φk−1∘∂k−−∂k+∘Φk)(p).

[F4]

The differentials are the trajectory counts of The mod-two Morse differential and The signed Morse differential over the integers; over Z/2 all signs are absent, and the continuation map is the count of The continuation chain map; this dictionary identifies the two sides of the coefficient computations below. Both maps are graded: ∂± and Φ lower, respectively preserve, the index, so coefficients vanish automatically outside the two cases considered.

[F5]

The actual metric-end differentials are defined and square to zero with these count and sign conventions (Arbitrary metric Morse--Smale end counts form finite Morse chain complexes).

Proof

technique · direct
1.1F1F5given

Fix k, a generator p∈Crit⁡k(f−) and a generator q∈Crit⁡k−1(f+), so that ind⁡(p)−ind⁡(q)=1. By [F1] the compactification C‾(p,q) is a compact one-manifold with boundary, and its boundary is the disjoint union of the once-broken products M−(p,a)×C(a,q) and C(p,b)×M+(b,q), each of them finite.

2.1F2F4step 1.1

Over Z/2, the boundary of C‾(p,q) has an even number of points by [F2]; counting the boundary points by their type gives ∑a#M−(p,a)#C(a,q)+∑b#C(p,b)#M+(b,q)≡0, which by the dictionary of [F4] is the q-coefficient of Φk−1∂−p+∂k+Φp; over Z/2 this sum vanishes, which is the asserted identity in the mod-two case.

2.2F2F3step 1.1

Over Z, [F2] makes the signed boundary count of the oriented compactification vanish; by [F3] the boundary signs are the products of the piece signs, and the differential and orientation normalization identifies this signed count with the q-coefficient of (Φk−1∂−−∂k+Φ)(p), which therefore vanishes.

3.1F4step 2.1step 2.2

Steps 2.1 and 2.2 cover every pair (p,q) of generators with ind⁡(p)=ind⁡(q)+1, and for all other pairs both sides of the identity have zero coefficient by the grading recorded in [F4]; extending linearly over the generators gives Φk−1∘∂k−=∂k+∘Φk for every k over both coefficient rings, i.e. a degree-zero morphism of chain complexes.

4.1step 3.1∎

A morphism of chain complexes induces a homomorphism on homology by the universal property of the homology functor, so [Φ]:HMk(f−,g−;Λ)→HMk(f+,g+;Λ) is well defined; this is the last assertion.

Depends on

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