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Continuous functional calculus properties

Statement

Assume AC. The continuous functional calculus on a nonzero complex Hilbert space preserves sums, products, conjugation and positivity, is norm-continuous, obeys continuous composition, sends eigenvectors at λ to scalar evaluation at λ, and commutes with every S satisfying ST=TS and ST=TS.

Facts & Assumptions

[A1]

The normal calculus ff(T) is an isometric unital star-isomorphism C(σ(T))C(I,T), hence complex-linear, multiplicative, unital, star-preserving and isometric; when T is self-adjoint, this normal calculus agrees function-by-function with the self-adjoint calculus, which has the same properties and range (Continuous functional calculus for bounded normal operators, Continuous functional calculus for bounded self adjoint operators).

[A2]

σ(f(T))=f(σ(T)) and f(T) is normal (Spectral mapping for continuous normal functional calculus).

[A3]

-polynomials are uniformly dense in the continuous functions on a compact subset of C (Complex Stone–Weierstrass dichotomy for separating self-adjoint algebras; the unital case is dense).

[A4]

C(I,T) is the norm closure of the unital -algebra of -polynomials in T, and multiplication in B(H) is continuous (C star algebra generated by a normal operator, Hilbert-adjoint identities).

[A5]

For normal T and Tx=λx one has Tx=λx: (Tλ)x2=(Tλ)(Tλ)x,x=(Tλ)x,(Tλ)x=0 by normality (Self-adjoint, positive, unitary and normal operators, Hilbert-adjoint identities).

[A6]

If X0 is a bounded positive operator then σ(X)[0,+) (Spectrum of a positive operator is nonnegative).

[A7]

AC is the hypothesis of the calculus and spectral suppliers (The Axiom of Choice).

Proof

technique · direct

Given: A nonzero complex Hilbert space H, a bounded normal TB(H), functions f,kC(σ(T)), a function hC(σ(f(T))), and an operator S commuting with T and T.

1.1

Linearity, multiplicativity, conjugation and norm-continuity hold: f(T) is the image of f under an isometric unital -isomorphism, so (f+k)(T)=f(T)+k(T), (fk)(T)=f(T)k(T), (λf)(T)=λf(T), f(T)=f(T) and f(T)=f.

A1
1.2

If f0 is real-valued, write f=r2 with r=f continuous; then f(T)=r(T)r(T) and f(T)x,x=r(T)x20, so f(T) is a positive operator; conversely, if f(T)0 as a quadratic form, then σ(f(T))[0,+) and [A2] gives f(σ(T))[0,+), so f0.

A1A2A6algebra
1.3

For every -polynomial q in z,z and every eigenvector x of T at λ, one has Tx=λx and hence q(T,T)x=q(λ,λ)x.

A4A5algebra
1.4

If S commutes with T and T, then S commutes with every -polynomial in T, and hence with every element of C(I,T) by continuity of multiplication.

A4algebra
2.1

Eigenvector identity: for eigenvectors x of T at λ and f continuous, approximate f uniformly on σ(T) by -polynomials qn; then f(T)x=limqn(T)x=limqn(λ,λ)x=f(λ)x.

step 1.3A1A3
2.2

Composition: since f(T) is normal and σ(f(T))=f(σ(T)), choose -polynomials qn converging uniformly to h on σ(f(T)). Multiplicativity and conjugation give qn(f(T),f(T))=(qn(f,f))(T). The left side converges to h(f(T)) by the isometry of the calculus for f(T), while the right side converges to (hf)(T) because qnfhf uniformly on σ(T). Thus h(f(T))=(hf)(T).

step 1.1A1A2A3algebra
2.3

Commutant: since f(T)C(I,T) and S commutes with all of C(I,T), Sf(T)=f(T)S.

step 1.4A4
3.1

The calculus therefore preserves sums, products, conjugation and positivity, is norm-continuous, obeys continuous composition h(f(T))=(hf)(T), sends eigenvectors at λ to the scalar f(λ), and commutes with every S commuting with T and T.

step 1.1step 1.2step 2.1step 2.2step 2.3A7

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