Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Irreducible unitary representations of compact groups are finite dimensional

Statement

Facts & Assumptions

Given: AC, a compact Hausdorff group K, and an irreducible strongly continuous unitary representation π of K on a nonzero complex Hilbert space H.

[F1]

Under AC there is a normalized Haar probability measure on K, and for every ξ∈H with ξ≠0 the rank-one average Qξ:=∫Kπ(k)Rξπ(k)−1 dμ(k), where Rξx=⟨x,ξ⟩ξ, is a well-defined bounded operator on H that is self-adjoint, nonzero, compact (Compact linear operator), and satisfies π(g)Qξ=Qξπ(g) for every g∈K (A positive rank-one Haar average is a nonzero compact intertwiner, Normalized Haar probability on a compact group, A bounded linear operator between normed spaces).

[F2]

Schur's lemma: for an irreducible strongly continuous unitary representation of a topological group on a nonzero complex Hilbert space, every bounded operator commuting with the representation is a scalar multiple of the identity (Schur lemma for complex unitary representations).

[F3]

If a nonzero scalar multiple cIH of the identity of a real or complex Hilbert space is a compact operator, then H admits an ordered basis of finite length; this implication is choice free (A nonzero compact scalar identity forces finite dimension).

[F4]

π is a group homomorphism, and IH≠0 because H≠{0} (Strongly continuous unitary representations, invariant linear subspaces and intertwiners).

Proof

technique · direct
1.1F1

Since H≠{0}, choose an element ξ∈H with ξ≠0, which is exactly the hypothesis under which [F1] applies. The operator Qξ of [F1] is therefore well defined, bounded, self-adjoint, nonzero, compact, and commutes with every operator π(g), that is, Qξπ(g)=π(g)Qξ for all g∈K.

2.1F2F4step 1.1

The operator Qξ is a bounded operator commuting with the irreducible representation π, so Schur's lemma [F2] provides a scalar c with Qξ=cIH. Since Qξ≠0 by step 1.1 while IH≠0 by [F4], the scalar satisfies c≠0.

3.1F3step 2.1∎

Now cIH=Qξ is a nonzero compact scalar identity with c≠0, so [F3] applied to the Hilbert space H shows that H admits an ordered basis of finite length. Hence every irreducible strongly continuous unitary representation of K is finite dimensional.

Depends on

Used by

Dependency tree · two levels

94 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources