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The discriminant is i<j(αiαj)2 and vanishes exactly when a monic polynomial has a repeated root

Statement

Let F be a field and let fF[t] be monic of degree n. In a splitting field write

f(t)=i=1n(tαi).

Then

Disc(f)=1i<jn(αiαj)2.

Moreover, Disc(f)=0 if and only if f has a repeated root. This criterion holds in every characteristic.

Facts & Assumptions

Given: A field F, a monic polynomial f, and a splitting field with roots α1,,αn.

[L1]

The discriminant is the coefficient expression obtained from Δn2, and in a split algebra it evaluates to Δn(α1,,αn)2 (The discriminant of a monic polynomial as the coefficient expression of Δn2).

[L2]

A splitting field presents f as a product of linear factors with roots counted according to multiplicity (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

[L3]

A root a of a nonzero polynomial is repeated if and only if f(a)=0 (A root is repeated exactly when it is also a root of the formal derivative).

Proof

technique · direct
1.1

Evaluate the coefficient expression in [L1] at the roots supplied by [L2]. The definition of Δn gives Disc(f)=i<j(αiαj)2.

givenL1L2
2.1

Because the splitting field is a field, this finite product is zero exactly when one factor αiαj is zero, equivalently when two entries in the root list coincide.

step 1.1algebra
3.1

Two entries coincide exactly when the linear factor at that root occurs at least twice, so f has a repeated root. By [L3] this agrees with the derivative criterion. No step divides by 2, so the equivalence remains valid in characteristic two.

step 2.1L2L3

Depends on

Used by

Dependency tree · next 3 levels

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