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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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The discriminant is ∏i<j(αi−αj)2 and vanishes exactly when a monic polynomial has a repeated root

Statement

Let F be a field and let f∈F[t] be monic of degree n. In a splitting field write

f(t)=∏i=1n(t−αi).

Then

Disc⁡(f)=∏1≤i<j≤n(αi−αj)2.

Moreover, Disc⁡(f)=0 if and only if f has a repeated root. This criterion holds in every characteristic.

Facts & Assumptions

Given: A field F, a monic polynomial f, and a splitting field with roots α1,…,αn.

[L1]

The discriminant is the coefficient expression obtained from Δn2, and in a split algebra it evaluates to Δn(α1,…,αn)2 (The discriminant of a monic polynomial as the coefficient expression of Δn2).

[L2]

A splitting field presents f as a product of linear factors with roots counted according to multiplicity (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

[L3]

A root a of a nonzero polynomial is repeated if and only if f′(a)=0 (A root is repeated exactly when it is also a root of the formal derivative).

Proof

technique · direct
1.1givenL1L2

Evaluate the coefficient expression in [L1] at the roots supplied by [L2]. The definition of Δn gives Disc⁡(f)=∏i<j(αi−αj)2.

2.1step 1.1algebra

Because the splitting field is a field, this finite product is zero exactly when one factor αi−αj is zero, equivalently when two entries in the root list coincide.

3.1step 2.1L2L3∎

Two entries coincide exactly when the linear factor at that root occurs at least twice, so f has a repeated root. By [L3] this agrees with the derivative criterion. No step divides by 2, so the equivalence remains valid in characteristic two.

Depends on

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Sources