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Eilenberg-Watts theorem for arbitrary unital rings

Statement

Let A,B be unital rings.

(i) For every (B,A)-bimodule M ((S,R)-bimodules and commuting left and right scalar actions) the functor TM=M⊗A−:A-Mod→B-Mod is additive, right exact, coproduct-preserving and therefore cocontinuous (Additive cocontinuous module functors and their schematic category), and the assignment M↦TM is functorial: a bimodule map f:M→M′ gives the natural transformation with components f⊗1X.

(ii) Conversely every additive cocontinuous functor F:A-Mod→B-Mod is naturally isomorphic to TF(A), where F(A) carries the (B,A)-bimodule structure ma=F(ra)(m) (F(A) is a (B,A)-bimodule for every additive functor F).

Hence, up to natural isomorphism, the additive cocontinuous functors are exactly the tensor functors with bimodule kernels: the quasi-inverse of M↦TM is F↦F(AA), with categorical language interpreted schematically as in Additive cocontinuous module functors and their schematic category. No commutativity of A or B is assumed and no choice is used.

Facts & Assumptions

Given: Unital rings A,B; the class of additive cocontinuous functors A-Mod→B-Mod; (B,A)-bimodules M,M′; an additive cocontinuous functor F; a bimodule map f:M→M′.

[F1]

A functor is additive cocontinuous when it is additive and preserves every small colimit (Additive cocontinuous module functors and their schematic category).

[F2]

The additive cocontinuous functors with all natural transformations as morphisms satisfy the category laws schematically, with a set of component codes for each fixed Hom-collection, componentwise identities and vertical composition (Natural transformations of additive cocontinuous module functors are determined at the regular module).

[F3]

An additive module functor is cocontinuous if and only if it is right exact and preserves arbitrary coproducts; equivalently if and only if it preserves cokernels and arbitrary direct sums (An additive module functor is cocontinuous exactly when it is right exact and preserves coproducts).

[F4]

TM=M⊗A− is additive, right exact and preserves arbitrary direct sums, including the empty one; if M is a (B,A)-bimodule then TM takes values in left B-modules and all displayed maps are B-linear (The functor M⊗A− is additive, right exact, and preserves direct sums over an arbitrary unital ring).

[F5]

Every bimodule map f:M→M′ yields a natural transformation TM⇒TM′ with components f⊗1X, and the assignment is compatible with identities and vertical composition (Natural transformations between tensor functors are bimodule maps).

[F6]

If F is additive and M=F(A), then ma=F(ra)(m) makes M a (B,A)-bimodule (F(A) is a (B,A)-bimodule for every additive functor F).

[F7]

If F is additive, right exact and coproduct-preserving and M=F(A) with that bimodule structure, then the canonical comparison τ:M⊗A−⇒F is a natural isomorphism (Canonical free presentations force the comparison to be an isomorphism).

[F8]

ρM:M⊗AA→M, ρM(m⊗a)=ma, is a group isomorphism (The regular module is a tensor unit: R⊗RN≅N and M⊗RR≅M).

Proof

technique · direct
1.1F1F2F3F4F5

For a (B,A)-bimodule M the functor TM is additive, right exact and coproduct-preserving by [F4], hence cocontinuous by the equivalence [F3]. Given a bimodule map f:M→M′, the components f⊗1X are natural in X and compatible with identities and vertical composition by [F5], so they define a morphism TM⇒TM′ in the category of [F2]; this makes M↦TM a functor from (B,A)-bimodules to the additive cocontinuous functors.

1.2F3F6F7

Let F be additive cocontinuous. By [F3] it is right exact and coproduct-preserving, and M:=F(A) is a (B,A)-bimodule by [F6]. The canonical comparison τ:M⊗A−⇒F is then a natural isomorphism by [F7], so F≅TF(A).

2.1F8step 1.1step 1.2

The two assignments are inverse up to natural isomorphism: for a bimodule M one has TM(A)=M⊗AA≅M by the unit isomorphism [F8], and for additive cocontinuous F one has F≅TF(A) by step 1.2. Steps 1.1 and 1.2 therefore show that, up to natural isomorphism, the additive cocontinuous functors A-Mod→B-Mod are exactly the functors TM with M a (B,A)-bimodule, with quasi-inverse F↦F(AA).

3.1step 1.1step 1.2step 2.1∎

The construction of τ used no presentation of any module and no element selection, and the module category is treated over arbitrary unital rings; hence neither commutativity of A or B nor the axiom of choice is used.

Depends on

Used by

Dependency tree · two levels

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Sources