Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Eventown: distinct A1,…,Am⊆[n] with every ∣Ai∣ and every ∣Ai∩Aj∣ even satisfy m≤2⌊n/2⌋

Statement

Let A1,…,Am be distinct subsets of [n]. If every ∣Ai∣ is even and every intersection ∣Ai∩Aj∣ with i≠j is even, then

m≤2⌊n/2⌋.

Facts & Assumptions

Given: distinct subsets A1,…,Am⊆[n] with every ∣Ai∣ even and every ∣Ai∩Aj∣ even for i≠j.

[L1]

Over F2, the standard-form values of all the incidence vectors vAi vanish against one another and against themselves (⟨vA,vB⟩ is the image of ∣A∩B∣ in F; over F2 it is 0 or 1 according to the parity of ∣A∩B∣).

[L3]

A d-dimensional vector space over F2 has 2d elements (A d-dimensional vector space over a field with q elements has exactly qd elements).

Proof

technique · direct
1.1L1given

Work over F2, and let U be the span of the incidence vectors vA1,…,vAm. By [L1], every pairing ⟨vAi,vAj⟩ is 0.

2.1step 1.1

Bilinearity then gives ⟨u,u′⟩=0 for all u,u′∈U, so U⊆U⊥.

3.1L2step 2.1

Writing d=dim⁡U, the inclusion of step 2.1 and [L2] give d≤n−d. Hence 2d≤n, so d≤⌊n/2⌋.

4.1L3step 3.1∎

The m distinct incidence vectors lie in U, so m≤∣U∣. By [L3], ∣U∣=2d≤2⌊n/2⌋, and therefore m≤2⌊n/2⌋.

Remarks

  • The floor enters only because d is an integer and 2d≤n. The proof is otherwise the same in both parities of n.

Depends on

Used by

Dependency tree · two levels

48 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources