Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-21
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Every derivative is Henstock–Kurzweil integrable and satisfies Newton–Leibniz

Statement

Let a<b, let F:[a,b]R be differentiable in the domain-relative sense, including one-sided endpoint derivatives, and put f=F. Every derivative is Henstock–Kurzweil integrable and its integral equals the endpoint increment:

abf=F(b)F(a).

No boundedness or prior integrability of f is assumed.

Every derivative is Henstock–Kurzweil integrable and its integral is the endpoint increment. Every derivative is Henstock–Kurzweil integrable and evaluates by endpoint difference.

Every derivative is Henstock–Kurzweil integrable and its integral equals the endpoint increment. Every derivative is Henstock–Kurzweil integrable.

Facts & Assumptions

Given: The differentiable function F and f=F.

[L2]

For every positive real r, there is a natural n1 with 1/n<r (For every ε>0 in a complete ordered field there is a natural n1 with 1/n<ε).

[L3]

Every nonempty subset of N has a least element (The well-ordering principle).

[L4]

Finite sums telescope: i=1m(cici1)=cmc0 (Laws of finite sums and finite products).

Proof

technique · direct
1.1

Given ε>0, put η=ε/(2(ba)). For each ξ[a,b], let N(ξ) be the least natural n1 such that the derivative estimate with error η holds whenever 0<yξ<1/n in the domain. Differentiability and [L2] make this set nonempty, and [L3] makes its least element unique; hence δ(ξ)=1/N(ξ) is a gauge defined without an uncountable choice.

givenL1L2L3
2.1

For a fine tagged cell, split F(vi)F(ui) at its tag, apply the two estimates from step 1.1, sum over all cells, and telescope by [L4]; the total error is below 2η(ba)=ε, proving the displayed HK value.

step 1.1L4algebra

Depends on

Used by

Dependency tree · two levels

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Sources