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Every finite-dimensional Noetherian local ring has a system of parameters
Statement
Let be a finite-dimensional Noetherian local ring, with . Then has a system of parameters.
Facts & Assumptions
Given: A finite-dimensional Noetherian local ring of dimension .
A first parameter can be chosen in outside every minimal prime, and for such a choice the quotient has dimension at most (Choose a parameter that misses the top-dimensional minimal components).
A system of parameters is a -tuple whose generated ideal has radical (Systems of parameters and parameter ideals).
Prime ideals of a quotient correspond to primes upstairs containing the quotient ideal (Prime ideals of a quotient ring are exactly the prime ideals containing the ideal).
Proof
If , the empty tuple is a system of parameters by [L2].
Assume and that the theorem is known in dimensions . By [L1], choose outside every minimal prime. Then is a Noetherian local ring of dimension at most . By the induction hypothesis, choose a system of parameters in of length . Lift those elements to .
The ideal generated by has radical in , so [L3] says the ideal has radical in . By [L2], the tuple is a system of parameters.
Therefore every finite-dimensional Noetherian local ring has a system of parameters.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Allen B. Altman and Steven L. Kleiman, A Term of Commutative Algebra, 13th ed., §21 (standard reference, not scraped)
- J. S. Milne, A Primer of Commutative Algebra, v4.03, §21 (standard reference, not scraped)
- Melvin Hochster, Dimension theory and systems of parameters (standard reference, not scraped)