Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-03
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Free groups on the same set are uniquely isomorphic compatibly with their generators

Statement

If (F,i) and (F′,i′) are free groups on the same set X, then there is a unique group isomorphism ϕ:F→F′ such that

ϕ∘i=i′.

Facts & Assumptions

Given: Two free groups (F,i) and (F′,i′) on X.

[L1]

A map from the generators of a free group extends uniquely to a group homomorphism (Free group on a set of generators).

[L2]

A group isomorphism is a bijective group homomorphism (Group isomorphisms, automorphisms and the set Aut⁡(G)).

Proof

technique · constructive
1.1

Apply the universal property of F to i′:X→F′ and construct the unique homomorphism ϕ:F→F′ with ϕi=i′.

L1givenconstruct
1.2

Apply the universal property of F′ to i:X→F and construct the unique homomorphism ψ:F′→F with ψi′=i.

L1givenconstruct
2.1

Both ψϕ and id⁡F are homomorphisms F→F whose composites with i equal i, so uniqueness in the universal property gives ψϕ=id⁡F.

step 1.1step 1.2L1
2.2

Symmetrically, ϕψ=id⁡F′.

step 1.1step 1.2L1
3.1

Thus ϕ is bijective, hence a group isomorphism.

step 2.1step 2.2L2
4.1

Any generator-compatible homomorphism F→F′ equals ϕ by the uniqueness in step 1.1; in particular the displayed isomorphism is unique.

step 1.1step 3.1L1L2discharge-construct: final∎

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources