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Fully relative Poincaré–Lefschetz duality

Statement

Assume AC. Let M be a compact R-oriented n-manifold with boundary D, where R is commutative unital. Suppose D=AB, where A,B are compact (n1)-manifolds with common boundary C=A=B=AB. Cap with the relative fundamental class gives an isomorphism Hp(M,A;R)Hnp(M,B;R),aa[M,D] for every integer p. The relative cap uses the compatible collar replacement proved below. Either piece or their intersection may be empty. AC is inherited from Poincaré–Lefschetz duality, with no additional choice principle used in the replacement.

Facts & Assumptions

[F1]

Poincaré–Lefschetz duality gives the actual cap isomorphisms Hk(X,X;R)Hmk(X;R) and Hk(X;R)Hmk(X,X;R) for compact oriented m-manifolds.

[F2]

Relative cap products with quotient domains displayed constructs the quotient-chain relative cap and its descent. Relative cup product for an excisive triad proves the chain and cochain equivalence from quotienting by the sum of two open-member subcomplexes to quotienting by chains on their union, including explicit operators 1P=E+E that preserve the union.

[F3]

Excision for singular homology and Excision for singular cohomology give the pair restriction isomorphisms under the closed-subset-in-interior hypothesis.

[F4]

Five lemma for a morphism of long exact sequences applies to the displayed exact windows.

[F5]

Long exact sequence of a pair and Long exact sequence of a pair in singular cohomology give the pair sequences. The latter's proof constructs connecting cocycles by extension and proves exactness element by element for the short exact cochain sequence.

[F6]

Compact topological manifold boundaries admit collars supplies collars of C in A and in B and the compact boundary manifold D of M.

[F7]

Homotopic maps induce equal maps in singular cohomology and Homotopic maps induce the same map on singular homology imply that the collar retractions give absolute homology and cohomology isomorphisms.

[F8]

A collar constructs the relative orientation class and its boundary class proves [M,D]=[D] and characterizes relative fundamental classes by their orientation restrictions on a compact collar core.

[F9]

Cap product boundary identity supplies the cap boundary sign. Cap naturality and projection formula proves naturality already on chains; the same equality passes to relative quotients whenever the indicated subspaces are preserved.

[F10]

The Axiom of Choice is assumed for the atlas and universal-coefficient uses inherited through [F1].

[F11]

Compatible orientation classes over compact subsets gives the unique compact-support orientation class on a boundaryless manifold and injectivity of its restrictions to all points of the compact support.

Proof

Given: The manifolds, decomposition, coefficients and orientation in the statement. Write z=[M,D]. The orientation on D is that of [F8]. Since BC=DA and AC=DB are open in D (both pieces are compact and hence closed), they have the restricted orientation; these are the orientations on the interiors of B,A. If A or B is empty, the assertion is exactly one of [F1]'s two maps. Empty D and dimension zero are thereby included. Assume both pieces are nonempty below.

1.1

If C, use [F6] to glue its two collars into a map c:C×(1,1)D, with negative height on A and positive height on B. This is a homeomorphism onto an open neighborhood of C. Indeed it is bijective onto the union of the two collar images, with their only intersection at C. The two halves are closed in the source and their images closed relative to the union, since A,B are closed in D; the two continuous inverse maps therefore paste continuously. The image is open: each complement of a collar image is closed in its compact piece, hence closed in D, and their union is the complement of the glued image. Fix 0<ϵ<1 and set U=Ac(C×[0,ϵ)) and V=Bc(C×(ϵ,0]). They are open in D: the complement of U is the closed collar complement in B, and similarly for V. They cover D and have intersection W=c(C×(ϵ,ϵ)). If C=, the disjoint compact pieces are open in D; set U=A,V=B,W=.

F6given
2.1

The space U deformation retracts onto A by replacing positive seam height t with (1s)t and fixing A. This is continuous at height zero by the collar coordinates, and outside the attached strip it is the identity. Likewise V retracts onto B. Denote the latter retraction by r. If C, set Cϵ=c(C×[0,ϵ))B. The retraction and its homotopy send W into W, with image Cϵ at the end, so (V,W) retracts onto (B,Cϵ). The inclusion CCϵ is also a deformation retract. For C=, take Cϵ= and all these maps are identities. By [F7], the pair sequences [F5] and [F4], the inclusions induce isomorphisms on relative homology and cohomology for (M,A)(M,U), (M,B)(M,V), (B,C)(B,Cϵ) and (B,Cϵ)(V,W). The maps of pair sequences commute directly on inclusion/quotient chains and restriction cochains; their connectors commute by lifting the same representative. Thus the five-lemma applications have their required naturality.

F4F5F7step 1.1
2.2

There is a short exact cochain sequence 0C(M,D;R)C(M,U;R)C(D,U;R)0. The last map is restriction. A cochain on D vanishing on U extends by zero on the other simplices of M and still vanishes on U, proving surjectivity in every degree. Its kernel is precisely the cochains vanishing on D. The resulting cohomology sequence is exact, with connector [γ][δγ~]: two extensions differ by a cochain vanishing on D, so they give the same relative class; changing γ by a coboundary and extending its primitive also changes that class by zero. Exactness at the middle term follows by subtracting an extended primitive when the restriction is a coboundary. At the right term, a connector that bounds allows subtracting the relative primitive from an extension to make it closed. At the left term, a relative cocycle bounding in C(M,U) is the connector of that primitive's restriction. These are all three positions, including the initial zero-degree injection because negative cochains vanish. Thus no unproved triple-sequence theorem is needed.

F5step 1.1
3.1

Put Q=C(M;R)/(C(U;R)+C(V;R)). Since U,V are open in their union D, [F2] gives the canonical chain equivalence q:QC(M,D;R) and its dual equivalence. Let z^=q1z. The relative cap of [F2] gives Sp:Hp(M,U;R)Hnp(M,V;R) by aaz^. Transport this map through the isomorphisms of step 2.1 to define the claimed map on (M,A) and (M,B). This is a compatible neighborhood replacement, rather than an assertion that arbitrary closed pieces form an open triad. If smaller positive collar widths are used with the same collars, inclusions commute with q and with the cap formula, so the transported map is unchanged. For two choices of collars, there are common smaller neighborhoods of this form: the compact sets A,B have open neighborhoods equal to the intersections of the respective U's and V's in D, and compactness of C puts sufficiently thin strips of the first collar inside these neighborhoods. This last assertion follows from finitely many product neighborhoods of points of C×{0}, taking the minimum of their finitely many positive widths. The same comparison through these inclusions shows independence of the collars.

F2step 1.1step 2.1
3.2

Restriction gives an isomorphism Hk(D,U)Hk(V,W) by [F3]: excise the closed set DV, which is contained in the open U. Together with step 2.1 this identifies Hk(D,U) with Hk(B,C). The analogous inclusion on relative homology is an isomorphism by the same excision. The class of [D] in Hn1(D,U) corresponds under this homology comparison to a class bV in Hn1(V,W). We prove that its image d=rbV in Hn1(B,Cϵ) is the image of [B,C]. Put N=BC and K=BCϵ. The collar makes Cϵ open in B, so K is compact and lies in the boundaryless manifold N. Excision of the closed set C inside Cϵ identifies Hn1(B,Cϵ) with Hn1(N,NK). At every xK, the retraction is the identity near x and the preceding excision comparison is induced by inclusion, so d restricts to the prescribed local generator inherited from [D]. By the pointwise injectivity and realization in [F11], d is the unique orientation class supported on K. The image of [B,C] has the same description: [F8] gives its prescribed generator at every point of N, hence at every point of K, and the same excision square transports those values. Therefore the two classes in Hn1(B,Cϵ) agree. If C is empty, K=B and the identical argument compares the absolute classes.

F3F8F11step 1.1step 2.1
4.1

It follows that Ek:Hk(D,U)Hn1k(V),[γ][(γV)bV] is an isomorphism. More precisely, first pass by step 3.2 to Hk(V,W), then restrict to Hk(B,Cϵ) and to Hk(B,C). Step 2.1 proves that these are isomorphisms; the last class caps with [B,C] by [F1] to give an isomorphism to Hn1k(B). Include B into V, an isomorphism on homology by step 2.1. This composite equals Ek. Indeed r and inclusion are inverse on the relative groups, rbV is the image of [B,C] by step 3.2, and the relative version of the literal chain naturality identity [F9] identifies the two cap outputs after r. Since r is an isomorphism on absolute homology, the outputs in V agree. This also proves that the definition of Ek is independent of all representatives.

F1F2F9F10step 2.1step 3.2
4.2

For use in the exact diagram, representatives can be chosen compatibly as follows. Start with a relative cycle v for z, so b=v is a cycle in D for [D], by [F8]. Use the operator E of [F2] for the open cover U,V of D, and replace v by vEb. Its boundary is Pb=bEb, since b=0, and lies in C(U)+C(V). Thus it represents z^ in Q. Write Pb=bU+bV by assigning each simplex in both members to U and each remaining simplex to its member. This is a specified linear splitting on the small simplex basis. Since bU=bV and the intersection of these simplex subcomplexes is C(W), bV is a relative cycle of (V,W) and represents precisely the excision class in step 3.2. In the rest of the proof use this adjusted v, so v=bU+bV.

F2F8step 3.1step 3.2
5.1

Use step 2.2's exact five-term window Hp1(D,U)δHp(M,D)Hp(M,U)Hp(D,U)δHp+1(M,D) above the pair homology window Hnp(V)Hnp(M)Hnp(M,V)(1)pHnp1(V)Hnp1(M). The five vertical maps are Ep1,Tp,Sp,Ep,Tp+1, where Tk is cap with z from [F1] for M. The first, second, fourth and fifth are isomorphisms by [F1] and step 4.1. Both rows are exact; the unit multiplying the homology connector leaves its kernel and image unchanged.

F1F2F5F10step 2.2step 4.1
6.1

All four squares commute using the adjusted cycle of step 4.2. A degree-(p1) cocycle γ on (D,U) extends to a cochain γ~ on (M,U) as in step 2.2. The cap with bU is zero, because it vanishes on all simplices in U. Thus [F9] gives δγ~v=γ~bV+(1)p(γ~v), which proves Tpδ=iEp1. Replacing p by p+1 proves the last square. The second square compares the same cap chain in M and modulo V, so commutes literally. For a cocycle φ on (M,U), [F9] gives (φv)=(1)pφbV, again because the bU term vanishes. Hence (1)pSp=Epres, the third square with precisely the chosen sign. For a negative source cochain degree these are the zero identities; all cap expressions of negative output degree are zero with the same boundary formula.

F2F9step 2.2step 4.2step 5.1
7.1

The five lemma [F4] applied to steps 5.1–6.1 proves that Sp is an isomorphism. Transporting through step 2.1 proves the claimed isomorphism of step 3.1. Empty pieces were handled in the Given paragraph; a disjoint decomposition with C= uses literal open pieces throughout. For the zero ring all groups and classes are zero. In dimension one the boundary pieces are zero-manifolds with empty common boundary and [F1] on each point is multiplication by its orientation unit. Empty M and dimension zero reduce to the ordinary empty-boundary case. All integer degrees, in particular p=0,n, have already been included in the exact-window computation; ordinary degree-zero groups are used. Degenerate simplices stay in their declared subspaces under face restriction and the small-chain operators. The only AC use is [F10]'s inherited atlas and local UCT choices in [F1]. Two supplied collars, finitely many compact-neighborhood widths, the explicit small-chain operator and extension by zero require no further AC or selection of component orientations.

F1F2F4F6F8F9F10step 2.1step 3.1step 5.1step 6.1

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