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Horvitz–Thompson exposure-specific mean is design-unbiased

Statement

Let U={(i,j):1≤i≤N, 1≤j≤ni} be a fixed population of M=∑ini units. Let Z have a known finite assignment law p and fixed potential-outcome schedule satisfying partial interference. Fix an exposure label d for which the mapping in Exposure mappings and exposure consistency is sufficient and πij(d)>0 for every (i,j)∈U. Then μ^HT(d)=1M∑(i,j)∈U1{Dij=d}Yijobsπij(d) is an estimator of the finite-population exposure mean μ(d)=M−1∑(i,j)∈UYij(d) and satisfies Ep[μ^HT(d)]=μ(d). Therefore, for two labels d,e with the same positivity and sufficiency conditions, μ^HT(d)−μ^HT(e) is design-unbiased for μ(d)−μ(e). Dependence among units' exposures does not affect these expectation identities.

Facts & Assumptions

Given: A finite assignment space Z with weights p(z) summing to one, fixed potential outcomes Yij(zi), a fixed finite population U, and an exposure label d satisfying the conditions in the Statement.

[F1]

Finite-population potential outcomes under partial interference: Yij(zi) is fixed for each allowed group assignment, and Yijobs=Yij(Zi).

[F2]

Exposure mappings and exposure consistency: Dij=fij(Zi), πij(d)=∑zp(z)1{fij(zi)=d}, and exposure sufficiency means Yij(zi)=Yij(d) whenever fij(zi)=d.

[F3]

Finite probability spaces, outcome weights, events, and event probabilities: the allowed assignments form a finite probability space with event probabilities given by their weights.

[F4]

Expectation of a real random variable on a finite probability space: expectation is the finite weighted sum E[X]=∑ω∈ΩX(ω)w(ω).

[F5]

Statistics and estimators: an estimator is a statistic with the target space of its estimand; here the assignment and observed outcomes form the data, and the displayed formula is a real-valued function of that data.

[F6]

Laws of finite sums and finite products: finite sums are additive and scaling distributes over them.

[F7]

Expectation is linear for every finite family of random variables, without any independence hypothesis: expectation distributes over every finite real linear combination on a finite probability space.

Proof

1.1F1F2F3F4given

Fix a unit (i,j). Since πij(d)>0, the finite sum for the design expectation of its weighted contribution is defined. By [F1], [F2], [F3], and [F4], Ep ⁣[1{Dij=d}Yijobsπij(d)]=1πij(d)∑z∈Zp(z)1{fij(zi)=d}Yij(zi). For every term with nonzero indicator, [F2] makes the outcome equal to the fixed value Yij(d); terms with zero indicator vanish.

2.1step 1.1F2givenalgebra

The remaining sum in step 1.1 is Yij(d)πij(d)/πij(d)=Yij(d) by the definition of πij(d) and its strict positivity.

3.1step 2.1F3F4F5F6F7givenalgebra

The population has finitely many units. By expectation linearity [F7], distributing the estimator's finite sum and applying step 2.1 to each unit gives Ep[μ^HT(d)]=M−1∑(i,j)∈UYij(d)=μ(d). The displayed map is a statistic with the same real target space as μ(d), so it is an estimator by [F5].

4.1step 3.1F4F7givenalgebra∎

Applying step 3.1 to each of d and e and distributing the same finite expectation over their difference by [F7] proves the exposure-contrast identity. The argument used only marginal exposure probabilities, so it requires no independence between units' exposures.

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