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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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Two-stage strategy-specific effect estimators are design-unbiased

Statement

Under the two-stage design of Two-stage randomized design and strategy-specific effects, for either strategy s∈{ϕ,ψ}, treatment value z∈{0,1}, and group i, E[Yˉ^i(z;s)∣Si=s]=Yˉi(z;s),E[Yˉ^i(s)∣Si=s]=Yˉi(s). Consequently, E[Yˉ^(z;s)]=Yˉ(z;s),E[Yˉ^(s)]=Yˉ(s). By taking the displayed contrasts, the design estimators of DE(ψ), IE(ϕ,ψ), TE(ϕ,ψ), and OE(ϕ,ψ) are unbiased. The proof does not require stratified interference or additive effects.

Facts & Assumptions

Given: The finite two-stage assignment law, fixed potential outcomes under partial interference, and the group and population targets and estimators in Two-stage randomized design and strategy-specific effects.

[F1]

Two-stage randomized design and strategy-specific effects: exactly Cs groups are assigned to each strategy s, and within group i under s exactly Kis of its ni units are chosen uniformly for treatment; the estimators divide by the fixed treatment-arm sizes and fixed group counts.

[F2]

Finite simple-random-sampling moment identities: under uniform fixed-size sampling from n units, each unit's inclusion probability is m/n, and the sample mean of fixed values has expectation equal to their finite-population mean.

[F3]
[F4]

Conditional expectation given a sigma algebra: a conditional-expectation version is measurable with respect to the conditioning sigma-algebra and has the same integrals on its events.

[F5]

Statistics and estimators: a statistic with the target space of an estimand is an estimator of that estimand.

[F6]

Estimands on a statistical model: an estimand is a specified function from the model's parameter set to its target-value set.

[F7]

Laws of finite sums and finite products: finite sums are additive and scaling distributes over finite sums.

[F8]

Conditional expectation on positive-probability events in finite spaces: positive-probability event conditioning is the finite conditional weighted sum, and averaging conditional means over a finite partition recovers unconditional expectation.

[F9]

Expectation is linear for every finite family of random variables, without any independence hypothesis: expectation distributes over finite real linear combinations on a finite probability space.

Proof

1.1F1F3F4F7F8F9given

Fix i,s,z. The number mizs of units with Zij=z is fixed and positive under [F1]. Each of the ni units has conditional probability mizs/ni of receiving z. Expanding the positive-probability event conditional mean by [F8] and distributing the finite sum over units by [F9] gives E[Yˉ^i(z;s)∣Si=s]=1mizs∑j=1niP(Zij=z∣Si=s)E[Yijobs∣Si=s,Zij=z]=1ni∑j=1niEi,s[Yij(Zi)∣Zij=z]=Yˉi(z;s). All conditioning events have positive probability by the bounds on Kis.

1.2F1F3F7F9given

By [F3], expectation linearity [F9] and the definition of Yˉi(s) give E[Yˉ^i(s)∣Si=s]=1ni∑j=1niEi,s[Yij(Zi)]=Yˉi(s). This uses no restriction on how one unit's outcome depends on other assignments within its group.

2.1step 1.1step 1.2F1F3F7F8F9algebra

Condition on the complete first-stage vector S. The denominators Cs are fixed, so expectation linearity [F9] and steps 1.1 and 1.2 yield E[Yˉ^(z;s)∣S]=1Cs∑i:Si=sYˉi(z;s),E[Yˉ^(s)∣S]=1Cs∑i:Si=sYˉi(s).

3.1step 2.1F2F3F7F8F9

The set of groups assigned strategy s is a uniform Cs-element subset of the N fixed groups. By [F2], each group has inclusion probability Cs/N, so the expectation of either average on the right of step 2.1 is the corresponding target population average. The finite-partition identity [F8] and expectation linearity [F9] prove the two population-mean identities.

4.1step 3.1F3F5F6F9algebra∎

Each effect estimator is the same finite linear contrast of estimated means as its target is of the corresponding target means. Distributing expectation over each contrast by [F9] and applying step 3.1 proves unbiasedness of all four effects. By [F5] and [F6], these statistic-valued contrasts are estimators of the displayed estimands.

Remarks

The assignment space and every sum in this proof are finite. The argument is choice-free and uses no conditional-expectation existence theorem on general probability spaces.

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