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A non-eigenfeature can give an unrestricted Gaussian MAP test level one
Statement
Assume the Axiom of Choice. Let be separable real Hilbert spaces, bounded and linear, , and let be a Borel Gaussian prior with mean and positive self-adjoint, injective, trace-class covariance , independent of a jointly Gaussian centered family indexed by , linear into with covariance . Put , , . For a feature vector , define , , and the raw test , where . Suppose , , and is not a scalar multiple of . Then the unrestricted null set satisfies The supremum need not be attained at any finite parameter value.
Statement references
Facts & Assumptions
Given: The Gaussian inverse model, operators, feature, and test in the Statement, together with the commutation and non-eigenfeature hypotheses.
Under the commutation hypothesis, , and the raw test has rejection probability when . Level, power, and weighted regularization of Gaussian MAP feature tests
The shifted normal operator is invertible, and its inverse commutes with . The shifted Hilbert-space normal operator is invertible with inverse norm at most
The adjoint identity is , and inner products satisfy Cauchy–Schwarz. The Hilbert-space adjoint of a bounded operator, Cauchy–Schwarz: , with equality exactly for dependent pairs
The Axiom of Choice is inherited from the posterior and polar-decomposition branches; Countable Choice is used for Hilbert adjoints and shifted-operator inversion. The Axiom of Choice, The Axiom of Countable Choice ()
Proof
Put . By [F1] and its inherited Axiom of Choice hypothesis [A1], . If for a real scalar , multiply the identity by and use [F2] to obtain , hence . The case forces , contrary to the hypothesis; otherwise . Thus any scalar dependence of and would make a scalar multiple of . The assumed non-eigenfeature condition therefore implies .
Let . Then , , and by orthogonal projection. For , belongs to . Moreover , since otherwise by invertibility of and would be an eigenvector with eigenvalue zero; so implies .
By [F3] and the inherited Axiom of Choice hypothesis [A1], the test statistic at has mean and positive standard deviation . The exact tail formula [F1] gives as . Every is null, so the supremum over is at least this limit and at most one; it is therefore one. Since a nondegenerate normal tail is strictly below one at every finite threshold, the limiting sequence does not assert attainment.
Depends on
- Gaussian MAP feature test
- Level, power, and weighted regularization of Gaussian MAP feature tests
- Gaussian posterior law in an isonormal inverse experiment
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- The Axiom of Choice
- Hilbert space
- The Hilbert-space adjoint of a bounded operator
- The shifted Hilbert-space normal operator is invertible with inverse norm at most $1/\lambda$
- Cauchy–Schwarz: $|\langle x,y\rangle|\le\|x\|\,\|y\|$, with equality exactly for dependent pairs
Used by
Dependency tree · two levels
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Sources
- Remo Kretschmann and Frank Werner, Maximum a posteriori testing in statistical inverse problems, Theorem 2.6 and its proof (standard reference, not scraped)