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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Level, power, and weighted regularization of Gaussian MAP feature tests

Statement

Assume the Axiom of Choice. Let X,H be separable real Hilbert spaces, K:X→H bounded and linear, ϵ>0, and let U be a Borel Gaussian prior with mean m0 and positive self-adjoint, injective, trace-class covariance C0, independent of a jointly Gaussian centered family Z indexed by H, linear into L2 with covariance E[Z(g)Z(k)]=⟨g,k⟩H. Fix h∈X, define S=C01/2, B=SK∗KS, R=(B+ϵ2I)−1, Φh=KSRSh, and ch=⟨Km0,Φh⟩H−⟨m0,h⟩X. Let Yx(g)=⟨Kx,g⟩H+ϵZ(g) and let the raw MAP test reject exactly when Yx(Φh)>ch. Define G(t)=∫−∞t(2π)−1/2e−s2/2 ds, the standard normal cumulative distribution function. For every x∈X its rejection probability is Px{Yx(Φh)>ch}={G ⁣(⟨x,K∗Φh⟩X−chϵ∥Φh∥H),Φh≠0,1{0>ch},Φh=0.

Let PY be the prior-predictive law of the field Y(g)=⟨KU,g⟩H+ϵZ(g) on RH with its cylinder sigma-algebra, and let Πy and My be the data-indexed posterior kernel and mean supplied by the Gaussian posterior-law theorem, using supplied finite or countable complete orthonormal bases of X and H as in that theorem. For every y, the scalar feature marginal under Πy is normal with mean ⟨My,h⟩X and variance ⟨Cposth,h⟩X; its mode is its mean, with the support point serving as the mode when the variance is zero. For each fixed h, the raw MAP test agrees for PY-almost every y with rejection exactly when this posterior marginal mode is positive. The exceptional null set may depend on h. If h=0, then Φh=ch=0, and the raw test returns 0 almost surely under every sampling law and under PY.

For a further real Hilbert space V and a continuous linear injection i:V→X, define the residual functional rΦ∈V∗, where V∗ is the continuous dual of V, by rΦ(v)=⟨Ki(v),Φ⟩H−⟨i(v),h⟩X,∥rΦ∥V∗=sup⁡∥v∥V≤1∣rΦ(v)∣. For 0<α<1 let z1−α satisfy G(z1−α)=1−α. If Φ≠0, the calibrated probe test rejects exactly when Yx(Φ)>ϵ∥Φ∥Hz1−α+∥rΦ∥V∗. Its rejection probability at every x∈X is the same displayed Gaussian-tail formula with Φ in place of Φh and calibrated threshold in place of ch. If x=i(v) satisfies ∥v∥V≤1 and ⟨x,h⟩X≤0, this test has rejection probability at most α. For Φ=0 it never rejects and has level zero.

As an additional weighted-regularization identity, assume Countable Choice and suppose that C0K∗K=K∗KC0. Let J be the real partial isometry in the polar decomposition K=J(K∗K)1/2. Let D={C01/2x:x∈X}, and define C0−1/2 as the inverse of C01/2 on D. On Ψ∈H, set Jh(Ψ)=∥K∗Ψ−h∥X2+ϵ2∥C0−1/2J∗Ψ∥X2 when J∗Ψ∈D, and set Jh(Ψ)=+∞ otherwise. Then Φh is a minimizer of Jh, and K∗Φh=B(B+ϵ2IX)−1h.

Facts & Assumptions

Given: The Gaussian model and hypotheses in the Statement, a feature vector h, a truth space V when the calibrated test is used, and the commutation hypothesis for the final clause.

[F1]

The MAP feature test has probe Φh=KC01/2(C01/2K∗KC01/2+ϵ2I)−1C01/2h and threshold ch=⟨Km0,Φh⟩−⟨m0,h⟩. Gaussian MAP feature test

[F2]

At any fixed x and probe Φ, Yx(Φ) is normal with mean ⟨Kx,Φ⟩H and variance ϵ2∥Φ∥H2; the zero probe is the constant zero. Isonormal Gaussian white-noise inverse experiment

[F3]

The standard normal distribution is continuous, strictly increasing, symmetric, and its upper 1−α quantile satisfies 1−G(z1−α)=α. The standard normal CDF has unique symmetric quantiles

[F4]

A positive injective trace-class covariance is compact and has a positive square root; its compact positive operator admits a complete orthonormal eigenbasis under Countable Choice. Trace class operator, Positive square root of a compact positive operator, Spectral theorem for compact self adjoint operators

[F5]

The cited partial-isometry definition uses nonzero complex Hilbert spaces; it supplies only the terminology here. The real operator J is constructed and its defining properties are verified directly in step 1.2. Isometry coisometry and partial isometry

[F6]

A self-adjoint operator on each finite-dimensional real inner-product space has an orthonormal eigenbasis, and Hilbert-basis expansions converge in norm with Parseval's identity. Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis, Fourier expansion in a Hilbert space, Parseval equivalences for an orthonormal family

[F7]

The Hilbert adjoint satisfies ⟨Kx,Φ⟩H=⟨x,K∗Φ⟩X. The Hilbert-space adjoint of a bounded operator

[F8]

For σ>0, the density of N(a,σ2) is uniquely maximized at a; when σ=0, N(a,0) is the point mass at a, whose support point is its mode.

[F9]

For every fixed h, the posterior-law theorem gives ⟨My,h⟩X=⟨m0,h⟩X+y(Φh)−⟨Km0,Φh⟩H for PY-almost every y, and gives the scalar posterior marginal stated in the Statement. Gaussian posterior law in an isonormal inverse experiment

[A1]

The posterior input inherits the Axiom of Choice from its separate conditional-law construction. Countable Choice is used for the compact spectral and square-root suppliers in the weighted clause; its real partial isometry is constructed in the proof. The Gaussian-tail and calibration calculations use no additional choice principle. The Axiom of Choice, The Axiom of Countable Choice (ACω)

Proof

1.1givenF1F2F3F7algebra

For fixed x and Φ≠0, [F2] gives Yx(Φ)=⟨Kx,Φ⟩H+ϵ∥Φ∥HZ0 in law, where Z0 is standard normal. By [F7], the mean is ⟨x,K∗Φ⟩X. Hence Px{Yx(Φ)>c}=1−G((c−⟨x,K∗Φ⟩)/(ϵ∥Φ∥)), which equals the stated formula by symmetry in [F3]. For Φ=0, Yx(0)=0 and the probability is exactly 1{0>c}. Substituting Φh,ch proves the raw MAP formula.

1.2givenA1F4F5F6F7algebra

For the weighted clause, [F4] gives the compact positive injective spectral decomposition C0vj=cjvj with cj>0, finite-dimensional eigenspaces, and a complete orthonormal family spanning X. The commutation hypothesis makes each such eigenspace invariant under the self-adjoint positive operator K∗K. By [F6], diagonalize its finite-dimensional restriction in each eigenspace. This gives a common complete orthonormal basis with C0vj=cjvj and K∗Kvj=λjvj, λj≥0. For λj>0, put wj=Kvj/λj; then ⟨wi,wj⟩H=δij by [F7]. Define Tvj=λjvj and define Jvj=wj for λj>0 and Jvj=0 for λj=0. For a finite sum x=∑jajvj, orthonormality gives ∥Tx∥2=∑jλj∣aj∣2≤∥K∥2∥x∥2 and ∥Jx∥2=∑λj>0∣aj∣2≤∥x∥2. Thus both rules extend by completeness to bounded real-linear operators on X, with T self-adjoint and positive and T2=K∗K. Any bounded self-adjoint positive square root Q of K∗K commutes with its square and therefore preserves each eigenspace; on an eigenspace with eigenvalue λ≥0, it equals λI. Indeed, for Q2=λI, a=λ, and a vector x in that eigenspace, V=(Q−aI)x satisfies QV=−aV, which positivity forces to vanish; when λ=0, ∥Qx∥2=⟨Q2x,x⟩=0. Hence T=(K∗K)1/2. Also ∥Kx∥2=∑jλj∣⟨x,vj⟩∣2, so ker⁡K is the closed span of the zero-eigenvalue vectors and (ker⁡K)⊥ is the closed span of the positive-eigenvalue vectors. The extended J vanishes on ker⁡K, is isometric on (ker⁡K)⊥, and has ker⁡J=ker⁡K by its coordinate formula; these real-space properties verify that J is a partial isometry as characterized in [F5], including when the basis is empty. The expansions of Kx and Jx show K=JT and R(K)‾=span⁡‾{wj:λj>0}. Since wj are orthonormal, with ξj=⟨Ψ,wj⟩H the adjoint identities and Fourier expansion in X give J∗Ψ=∑λj>0ξjvj and K∗Ψ=∑λj>0λjξjvj. If hj=⟨h,vj⟩X, the Fourier expansions give ∥K∗Ψ−h∥X2=∑λj>0∣λjξj−hj∣2+∑λj=0∣hj∣2 and ∥C0−1/2J∗Ψ∥X2=∑λj>0∣ξj∣2/cj whenever the second term is defined. Components of Ψ in R(K)‾⊥ affect neither expression.

1.3F2F8F9algebra

For each fixed h, [F9] gives for PY-almost every y that ⟨My,h⟩X=⟨m0,h⟩X+y(Φh)−⟨Km0,Φh⟩H=y(Φh)−ch. For every y, the posterior feature marginal has the normal law stated in the theorem. If its variance σ2 is positive, its density is (σ2π)−1exp⁡(−(t−⟨My,h⟩X)2/(2σ2)), uniquely maximized at ⟨My,h⟩X; if its variance is zero, it is the point mass at that same value. Thus its mode is ⟨My,h⟩X in both cases. On the probability-one set where the displayed identity holds, the raw comparison y(Φh)>ch is therefore equivalent to a positive posterior marginal mode; its exceptional null set may depend on h. If h=0, the definitions give Φh=ch=0, and [F2] gives Yx(0)=0 almost surely under each Px and Y(0)=0 almost surely under PY, so the raw test returns 0 under all those laws.

2.1givenF2F3F7step 1.1algebra

For x=i(v) in the stated null ball, [F7] gives ⟨Kx,Φ⟩=⟨x,K∗Φ⟩X=⟨x,h⟩X+rΦ(v)≤∣rΦ(v)∣≤∥rΦ∥V∗. Thus the calibrated threshold is at least ⟨Kx,Φ⟩+ϵ∥Φ∥z1−α. Applying step 1.1 to that threshold and using [F3] bounds the rejection probability by 1−G(z1−α)=α. The same substitution gives the exact stated power formula at every x. If Φ=0, then r0(v)=−⟨i(v),h⟩ and its norm is nonnegative, so the strict comparison is 0>∥r0∥V∗, which is false; the level and power are zero.

3.1step 1.2F4F6F7algebra∎

For each λj>0, the scalar quadratic ∣λjξ−hj∣2+ϵ2∣ξ∣2/cj is minimized at ξj=λjcjhj/(λjcj+ϵ2). These coefficients define a vector in H and lie in the inverse-square-root domain because ∣ξj∣2/cj=λjcj∣hj∣2/(λjcj+ϵ2)2≤∣hj∣2/(4ϵ2), using t/(t+ϵ2)2≤1/(4ϵ2) for t≥0; Parseval makes the bound summable. The corresponding vector is KSRSh=Φh, since SRS has coefficient cjhj/(λjcj+ϵ2) on vj. Each coordinate minimizes its summand, while the λj=0 terms are fixed and the orthogonal observation component is irrelevant, so Φh minimizes Jh. Finally [F7] and the diagonal action of B show that K∗Φh has coefficient λjcjhj/(λjcj+ϵ2), which is the coefficient of B(B+ϵ2I)−1h.

Remarks

The raw MAP formula uses a prior fixed independently of the observation whose rejection is tested. If prior covariance is tuned using the same sample, this theorem does not establish the displayed level or power formula for that empirical procedure.

Polar factorization diagram

The triangle records the real polar factorization K=J(K∗K)1/2. On the common eigenbasis in step 3.1, the upper arrow sends vj to λjvj; the right arrow then sends it to λjwj when λj>0, and to zero when λj=0. This agrees with the lower arrow K on the basis and therefore on all of X by boundedness and density. The diagram summarizes step 1.2 and is not used in any proof step.

XXH(K¤K)1=2KJ

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