Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Jordan decomposition lies inside a complex semisimple Lie algebra

Statement

Assume the Axiom of Choice. Every element x of a finite-dimensional complex semisimple Lie algebra g has a unique abstract Jordan decomposition x=xs+xn, and adxs, adxn are the additive Jordan–Chevalley parts of adx.

Facts & Assumptions

Given: The Axiom of Choice, a finite-dimensional complex semisimple Lie algebra g, and an element xg.

[A1]

The Axiom of Choice is The Axiom of Choice; it is inherited through [L1] and [L2], with [L2] itself using the operator theorem [L1].

[L1]

Under the Axiom of Choice, every endomorphism of a finite-dimensional vector space over a perfect field has a unique additive Jordan–Chevalley decomposition into commuting semisimple and nilpotent parts (Over a perfect field, every endomorphism has a unique commuting semisimple-plus-nilpotent decomposition, polynomial in the endomorphism).

[L2]

Under the Axiom of Choice, if adx=S+N is that additive decomposition, there are unique ys,yng with S=adys and N=adyn; they give the unique abstract Jordan decomposition of x. Conversely, any abstract Jordan decomposition has adjoints S,N (Jordan–Chevalley parts agree under the adjoint representation).

[L3]

An abstract Jordan decomposition is a decomposition x=xs+xn with commuting parts whose adjoints are semisimple, respectively nilpotent (Abstract Jordan decomposition).

Proof

technique · direct
1.1

The endomorphism adx of the finite-dimensional complex vector space g has an additive Jordan–Chevalley decomposition by [L1]. Applying clause (ii) of [L2] to it produces elements ys,yng such that x=ys+yn, [ys,yn]=0, adys is semisimple and adyn is nilpotent, and such that adys, adyn are the additive parts of adx. By [L3] this is an abstract Jordan decomposition of x.

A1L1L2L3
2.1

Let x=u+v be any abstract Jordan decomposition. Clause (i) of [L2] identifies adu and adv with the additive Jordan–Chevalley parts of adx, which are the parts adys and adyn produced in step 1.1; uniqueness of the abstract decomposition in [L2] then gives u=ys and v=yn. For g=0 the only element is 0 and the decomposition 0=0+0 satisfies the definition vacuously; the Axiom of Choice enters only through [L1] and [L2].

A1L1L2L3step 1.1

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