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Lipschitz stability of strongly monotone variational inequalities

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let H be a real Hilbert space (Hilbert space), let K⊆H be nonempty, closed and convex, let a be a bounded coercive bilinear form with constants M,α>0 (Bounded, coercive and symmetric sesquilinear forms), and let F1,F2∈H∗ with the dual norm ∥⋅∥∗ (The dual space X^* of a normed space and its dual norm, The operator norm as the least bound and as the unit-sphere or unit-ball supremum). Let ui∈K be the unique solution of the variational inequality with data Fi, that is, a(ui,v−ui)≥Fi(v−ui) for every v∈K (Stampacchia's variational inequality). Then α∥u1−u2∥≤∥F1−F2∥∗.

Facts & Assumptions

Given: A real Hilbert space H, a nonempty closed convex K⊆H, a bounded coercive bilinear form a with constants M,α>0, bounded linear functionals F1,F2 on H, and their unique variational solutions u1,u2∈K.

[A1]

The Axiom of Countable Choice (ACω): Countable Choice, consumed through the existence-and-uniqueness theorem for the variational inequality.

[F1]

Stampacchia's variational inequality: for each bounded linear functional F on H there is exactly one u∈K with a(u,v−u)≥F(v−u) for every v∈K; in particular u1 and u2 are well defined and satisfy a(u1,v−u1)≥F1(v−u1) and a(u2,v−u2)≥F2(v−u2) for all v∈K.

[F2]

Bounded, coercive and symmetric sesquilinear forms: a is bilinear with a(u,u)≥α∥u∥2 for every u∈H.

[F3]

The dual space X^* of a normed space and its dual norm, The operator norm as the least bound and as the unit-sphere or unit-ball supremum: H∗ is the normed space of bounded linear functionals with dual norm ∥G∥∗=sup⁡{∣G(w)∣:∥w∥≤1}, so ∣G(w)∣≤∥G∥∗∥w∥ for every w∈H; in particular F1−F2∈H∗.

Proof

technique · direct

Given: The setting above, with the unique solutions u1,u2∈K of the two variational inequalities.

1.1givenA1F1

Testing the inequality for u1 at the admissible point v=u2 and the inequality for u2 at v=u1 [F1] gives a(u1,u2−u1)≥F1(u2−u1) and a(u2,u1−u2)≥F2(u1−u2).

2.1step 1.1F2algebra

Adding the two inequalities of step 1.1 and using bilinearity [F2] gives a(u1−u2,u2−u1)≥(F1−F2)(u2−u1), that is, −a(u1−u2,u1−u2)≥(F1−F2)(u2−u1); coercivity [F2] bounds the left-hand side by −α∥u1−u2∥2, so α∥u1−u2∥2≤−(F1−F2)(u2−u1)=(F1−F2)(u1−u2).

3.1step 2.1A1F3algebra∎

If u1=u2 the asserted inequality is trivial. Otherwise the dual-norm estimate [F3] gives (F1−F2)(u1−u2)≤∥F1−F2∥∗∥u1−u2∥, so step 2.1 yields α∥u1−u2∥2≤∥F1−F2∥∗∥u1−u2∥; dividing by the positive number ∥u1−u2∥ gives α∥u1−u2∥≤∥F1−F2∥∗, which is the assertion; Countable Choice was used only through the existence and uniqueness theorem [A1].

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