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TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-14
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Local normal form near a coisotropic submanifold

Statement

Assume ACω. For j=0,1, let ij:Cj(Mj,ωj) be a closed coisotropic embedding. If f:C0C1 is a diffeomorphism satisfying fi1ω1=i0ω0, then f extends to a symplectomorphism between neighbourhoods of C0 and C1. Thus the presymplectic form on a coisotropic submanifold, whose kernel is its characteristic distribution, determines the local symplectic germ.

Facts & Assumptions

Given: ACω and the two coisotropic embeddings and map in the statement.

[F1]

The characteristic bundle K=ker(iω) is smooth and involutive. Characteristic distribution of a coisotropic submanifold is involutive.

[F2]

An involutive constant-rank distribution has foliation coordinates. Frobenius local coordinate theorem.

[F3]

Every smooth vector subbundle has a smooth complement. Every vector subbundle has a smooth complement.

[F4]

Under ACω, closed embeddings have tubular neighbourhoods, and relative Moser corrects forms agreeing along the embedded submanifold. The tubular neighbourhood theorem in a smooth ambient manifold, Relative Poincaré primitive near a submanifold, Relative Moser theorem.

Proof

technique · direct
1.1

By [F1]--[F2], Kj integrates locally to the characteristic foliation. The equality of restricted forms gives df(K0)=K1. By [F3], choose a smooth complement E0 to K0 in TC0 and put E1=df(E0). Each Ej is symplectic: if eEj is orthogonal to Ej, it is also orthogonal to Kj because Kj=TCjωj, hence to all of TCj; thus eKjEj=0. Consequently TMjCj=EjSj,Sj=Ejωj, where Sj is a smooth symplectic subbundle of rank 2rankKj and KjSj is Lagrangian. Smoothness follows locally by solving the constant-rank linear equations defining the symplectic orthogonal.

F1F2F3givenalgebra
2.1

Choose by [F3] a smooth complement Gj to Kj in Sj. The pairing Kj×GjR, (k,g)ωj(k,g), is nondegenerate. There is therefore a unique smooth bundle map Tj:GjKj satisfying ωj(Tjg,h)=12ωj(g,h)(g,hGj). For Gj={g+Tjg:gGj}, skew-symmetry gives ωj(g+Tjg,h+Tjh)=ωj(g,h)12ωj(g,h)+12ωj(h,g)=0. Thus Sj=KjGj is a Lagrangian splitting. Define A:G0G1 by the nondegenerate-pairing condition ω1(df(k),A(g))=ω0(k,g)(kK0). It is a smooth bundle isomorphism. The map equal to df on E0K0 and to A on G0 preserves the symplectic form on every summand and cross-pairing, hence is a symplectic bundle isomorphism TM0C0TM1C1 extending df.

F3step 1.1algebra
3.1

The quotient maps identify the chosen complements Gj with the quotient normal bundles. Apply the tubular construction in [F4] using these complements: explicitly, in the proof of that construction replace the orthogonal complement by Gj in the normal-addition map. Its derivative at (x,0) is then (u,g)dij(u)+g; the same inverse-function and variable-radius shrinking argument produces a tubular diffeomorphism Ψj with that derivative. The bundle map induced by A:G0G1 therefore gives h=Ψ1AΨ01, a diffeomorphism between neighbourhoods extending f with dhC0 equal to the full symplectic bundle isomorphism of step 2.1, not merely equal on quotient normals. Hence hω1 and ω0 agree as full tensors along C0. Their difference is closed and has the fibre-radial relative primitive supplied in [F4].

F4step 2.1construct
4.1

The interpolation between those two forms is symplectic near C0. Relative Moser therefore gives a correction fixed on C0; composing it with h produces the desired neighbourhood symplectomorphism. The characteristic foliation was derived in step 1.1 rather than assumed as extra data.

F4step 1.1step 2.1step 3.1

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