Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Margulis family has uniform spectral gap

Statement

For every m≥2 the normalized Margulis adjacency has absolute nontrivial norm α≤73/80, hence algebraic gap at least 7/80. For m=1 the mean-zero space is zero and α=0.

Facts & Assumptions

Given: the objects and hypotheses in the statement above.

[F1]

For every integer m≥1 and every nonnegative function g on (Z/mZ)2 with g(0)=0, the quadratic expression Q in the Fourier reduction satisfies Q(g)≤7320∑zg(z)2. Consequently, for the forward/full adjacency operators and normalized transform in that reduction, ∣⟨f,Af⟩∣≤(73/10)∥f∥2 for real mean-zero f. (Margulis diamond weight bound).

[F2]

Let V be a finite-dimensional real inner product space and let T:V→V be self-adjoint. Then V has an orthonormal basis consisting of eigenvectors of T. (Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis).

Proof

1.1F1

The diamond bound and its Fourier consequence give ∣⟨f,Af⟩∣≤(73/10)∥f∥2 for every real mean-zero f. Divide by the degree eight to get ∣⟨f,Mf⟩∣≤(73/80)∥f∥2.

2.1F2step 1.1∎

The mean-zero subspace is invariant and M is real symmetric. In its orthonormal eigenbasis the preceding bound applied to each eigenvector gives ∣μ∣≤73/80, so the operator norm has that bound. This controls negative as well as positive eigenvalues; in particular 1−μ2≥7/80. For m=1 use the zero-space norm convention directly.

Depends on

Used by

Dependency tree · two levels

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Sources