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Stable mixed curl-curl formulation with kernel gauge

Statement

Assume Countable Choice for the graph spaces and real L2 product as in Kernel quotient and gauge for discrete curl-curl. Let Vh be that finite-dimensional real edge space, Kh=ker⁡(curl⁡∣Vh), and Zh=Vh∩Kh⊥. Here Vh∗=Hom⁡R(Vh,R) is the algebraic dual of Linear functionals and the algebraic dual V∗=L(V,F). For every f∈Vh∗ there is a unique pair (uh,ph)∈Zh×Kh satisfying (curl⁡uh,curl⁡vh)L2+(ph,vh)L2=f(vh)(vh∈Vh),(uh,qh)L2=0(qh∈Kh). The gauge multiplier is the L2 Riesz representative of f∣Kh. The quotient solution satisfies the exact stability identity ∥curl⁡uh∥L2=∥f∣Zh∥(Zh,∥curl⁡(⋅)∥L2)∗,∥ph∥L2=∥f∣Kh∥(Kh,∥⋅∥L2)∗. The constraint form b(v,q)=(v,q)L2 has inf-sup constant one when Kh≠{0}, Vh has the H(curl⁡) graph norm and Kh has the L2 norm; if Kh={0} the constraint is vacuous. The curl form is coercive with constant one on Zh in the quotient curl norm. No mesh-uniform estimate in the full graph norm is claimed here.

Facts & Assumptions

Given: The finite-dimensional real space Vh, its kernel and orthogonal gauge from Kernel quotient and gauge for discrete curl-curl, and a linear functional f∈Vh∗.

[A1]

Countable Choice is inherited from the graph-space uniqueness and real L2 product interfaces; the finite-dimensional Riesz and orthogonal-decomposition arguments use no stronger choice axiom. (The Axiom of Countable Choice (ACω))

[F1]

Kh is the curl kernel, Zh=Vh∩Kh⊥, and ∥[vh]∥curl⁡=∥curl⁡vh∥2 is the quotient norm. (Kernel quotient and gauge for discrete curl-curl)

[F2]

A finite-dimensional real inner-product space splits as W⊕W⊥. (For a subspace W of a finite-dimensional inner product space, V=W⊕W⊥)

[F3]

Every real linear functional on a finite-dimensional real inner-product space is represented uniquely by inner product with a vector. (Finite-dimensional Riesz representation: every functional is uniquely v↦⟨v,w⟩)

[F4]

Vh∗ consists of all real linear functionals on Vh. (Linear functionals and the algebraic dual V∗=L(V,F))

Proof

1.1A1F1F3F4givenconstruct

On Zh, the bilinear form ah(u,v)=(curl⁡u,curl⁡v)L2 is an inner product: if ah(u,u)=0, then u∈Kh and u∈Kh⊥, hence u=0. The finite-dimensional Riesz theorem [F3] applied to f∣Zh gives a unique uh∈Zh with ah(uh,zh)=f(zh) for every zh∈Zh. Applying [F3] to the L2 inner product on the finite-dimensional Kh gives a unique ph∈Kh with (ph,qh)L2=f(qh) for all qh∈Kh. The zero subspace cases are included in [F3].

2.1A1F1F2step 1.1algebra

Restrict the L2 inner product to the finite-dimensional space Vh. Its orthogonal complement of Kh is Vh∩Kh⊥=Zh by [F1], so [F2] gives Vh=Zh⊕Kh. Thus each vh has a unique orthogonal decomposition vh=zh+qh. Since curl⁡qh=0 and (ph,zh)=0, the two identities of step 1.1 give ah(uh,vh)+(ph,vh)=f(zh)+f(qh)=f(vh). Also uh∈Zh gives the gauge equation. Any solution must restrict to the unique Riesz problems on Zh and Kh, proving uniqueness.

3.1A1F1F2F3step 1.1step 2.1algebra∎

For any real inner product c(⋅,⋅) and any nonzero w, positivity of c(v−tw,v−tw) at t=c(v,w)/c(w,w) gives ∣c(v,w)∣2≤c(v,v)c(w,w); if w=0 the inequality is immediate. Thus the norm of the functional z↦c(u,z) is at most ∥u∥c, and when u≠0 equality is attained at z=u; when u=0 both sides vanish. Applying this argument to ah and the L2 product, together with the Riesz identities of step 1.1, proves both exact dual-norm identities. For the constraint, if qh≠0 choose vh=qh; then curl⁡qh=0, ∥vh∥H(curl⁡)=∥qh∥2, and b(vh,qh)=∥qh∥22, so the inf-sup constant is at least one. For the upper bound, the same positive-square argument with the L2 inner product gives ∣b(vh,qh)∣≤∥vh∥2∥qh∥2≤∥vh∥H(curl⁡)∥qh∥2. On Zh, ah(vh,vh)=∥[vh]∥curl⁡2, which gives coercivity constant one in the declared quotient norm.

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