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Norm limit of compact operators is compact
Statement
Assume the Axiom of Countable Choice (The Axiom of Countable Choice ()). Let be a normed space, let be a Banach space (Banach space), and let , , be compact operators (Compact linear operator) with for a bounded linear operator (A bounded linear operator between normed spaces, The operator norm as the least bound and as the unit-sphere or unit-ball supremum, Convergence of a sequence in a metric space: iff in ). Then is compact.
Facts & Assumptions
is compact exactly when is compact, where (Compact linear operator); and for every (The operator norm as the least bound and as the unit-sphere or unit-ball supremum, A bounded linear operator between normed spaces).
A compact metric space has a finite subcover of every open cover; in particular, if every point of has a ball of the family containing it, then finitely many of these balls cover (Open cover, subcover, compact metric space, and compact subset of a metric space, Open ball, closed ball and sphere in a metric space). Selecting one index from each of finitely many nonempty index sets is possible without choice (Every natural-number-indexed list of nonempty sets has a choice function on its family of values).
For nonempty in a metric space, (claim 1 of The closure of a nonempty is , equals together with its limit points, and is the smallest closed superset); so for and real there is with (Open ball, closed ball and sphere in a metric space).
A subset of a metric space is totally bounded when for every real there are finitely many points with (Finite -net and totally bounded metric space, Open ball, closed ball and sphere in a metric space).
A closed subset of a complete metric space is complete (claim 2 of Closed subspaces of complete metric spaces are complete; the converse under countable choice), and a Banach space is a complete normed space (Banach space); a complete and totally bounded metric space is compact under (A complete, totally bounded metric space is compact, proved from countable choice used exactly once).
Proof
Given: , a normed space , a Banach space , compact operators with , and .
For every real there is with : this is exactly the convergence in the norm metric of .
For every and every real there is with , because , the set is nonempty, and [A3] applies to .
Each is compact by [A1].
Whenever is a totally bounded nonempty subset of a metric space, its closure is totally bounded: given , [A4] gives finitely many points with ; for there is with by [A3], and for some , so ; hence the same finite set, whose points lie in , is an -net for .
The set is closed in the complete space , hence a complete metric space by [A5].
Fix a real and choose with by [step 1.1]. The family of balls , , covers by [step 1.2]; since is compact by [step 1.3], finitely many indices satisfy , and one may pick these finitely many indices by [A2]. For every the point lies in , so some has ; writing and using gives ; thus is a finite -net for with centres in , and is totally bounded.
By [step 1.4] the closure is totally bounded as well, its finite nets having centres in that closure.
The space is complete by [step 1.5] and totally bounded by [step 3.1]; by [A5] it is compact, and therefore is compact by [A1].
Depends on
- Compact linear operator
- A bounded linear operator between normed spaces
- The operator norm as the least bound and as the unit-sphere or unit-ball supremum
- Open cover, subcover, compact metric space, and compact subset of a metric space
- Open ball, closed ball and sphere in a metric space
- Finite $\varepsilon$-net and totally bounded metric space
- Convergence of a sequence in a metric space: $x_k \to x$ iff $d(x_k, x) \to 0$ in $\mathbb{R}$
- Banach space
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- A complete, totally bounded metric space is compact, proved from countable choice used exactly once
- Closed subspaces of complete metric spaces are complete; the converse under countable choice
- The closure of a nonempty $A$ is $\{x : d(x,A) = 0\}$, equals $A$ together with its limit points, and is the smallest closed superset
- Every natural-number-indexed list of nonempty sets has a choice function on its family of values
Used by
- Compact operator iff approximation numbers tend to zero Corollary
- Approximable operator Definition
- Calkin algebra Definition
- Diagonal operator on ell p is compact iff diagonal tends to zero Example
- Diagonal Schatten class criteria on ell two Example
- Positive square root of a compact positive operator Lemma
- Hilbert–Schmidt operators are compact Theorem
- Trace class is a two sided Banach operator ideal Theorem
Dependency tree · two levels
58 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Gerald Teschl, Topics in Real and Functional Analysis, version November 17, 2017 — §3.1 p.70, Theorem 3.2 (standard reference, not scraped)
- Theo Bühler and Dietmar Salamon, Functional Analysis — §4.2 pp.185–186, Theorem 4.28(ii) (standard reference, not scraped)