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Every nontrivial normal subgroup of a finite -group meets the center nontrivially
Statement
Let be a finite -group and let be nontrivial. Then
Facts & Assumptions
Given: A finite -group and a nontrivial normal subgroup .
A finite -group has prime-power order (A finite -group has order for a prime and some ).
A finite -group action satisfies the fixed-point congruence (If a finite -group acts on a finite set , then ).
Conjugation by is an automorphism (Conjugation is an automorphism).
The center consists of the elements fixed by every conjugation (The center of a group).
A nontrivial subgroup of a finite -group has order for some (Every subgroup of a finite -group has order a power of ).
Proof
By [L3] and [L4], conjugation restricts to an action of on the finite set .
A point of is fixed by every element of exactly when it lies in by [L5].
By [L6], divides . Applying [L2] to the action in step 1.1 therefore shows that divides .
The intersection contains , and its cardinality is a positive multiple of the prime ; hence it contains a nonidentity element.
Depends on
- A finite $p$-group has order $p^n$ for a prime $p$ and some $n\in\mathbb N$
- If a finite $p$-group $P$ acts on a finite set $X$, then $|X|\equiv|X^P|\pmod p$
- Normal subgroup: invariance under conjugation
- Equivalent characterisations of a normal subgroup by conjugates and left and right cosets
- Conjugation $x\mapsto gxg^{-1}$ is an automorphism
- The center $Z(G)$ of a group
- Every subgroup of a finite $p$-group has order a power of $p$
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 86 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- K. Conrad, Group Actions, Theorem 5.3 (standard reference, not scraped)