Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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If a finite p-group P acts on a finite set X, then ∣X∣≡∣XP∣(modp)

Statement

If a finite p-group P acts on a finite set X, then

∣X∣≡∣XP∣(modp).

Facts & Assumptions

Given: A finite p-group P acting on a finite set X.

[L1]
[L2]

The global fixed-point set is XP={x:g⋅x=x for every g∈P} (The fixed-point sets Xg and XG of a group action).

[L5]

Every subgroup of P has prime-power order (Every subgroup of a finite p-group has order a power of p).

[L6]
[L8]

Finite sums over finite index sets are well-defined (The sum ∑i∈Sai over a finite index set, and its product form).

Proof

technique · direct
1.1

By [L3], X is the disjoint union of its P-orbits. An orbit is a singleton exactly when its point is fixed by every element of P, so the singleton orbits are indexed by XP.

L2L3
1.2

For a non-singleton orbit P⋅x, the stabilizer Px is proper. By [L1], [L4], and [L5], its index is a positive power of p, so p divides ∣P⋅x∣.

L1L4L5
2.1

Applying [L7] and [L8] to the orbit partition, every non-singleton orbit contributes a multiple of p and the singleton orbits contribute ∣XP∣. Thus p divides ∣X∣−∣XP∣, which is the asserted congruence by [L6].

step 1.1step 1.2L6L7L8∎

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