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For an integrable f, the one-sided derivatives of F(x)=axf equal the corresponding one-sided limits of f; at a jump they are unequal

Statement

Let a<b, let f:[a,b]R be Riemann integrable, and put F(x)=axf.

  1. If c[a,b) and limxc+f(x)=L+, then the right derivative exists and F+(c)=L+.
  2. If c(a,b] and limxcf(x)=L, then the left derivative exists and F(c)=L.

In particular, if both one-sided limits exist at an interior point and are unequal, then F is not differentiable there. The value f(c) itself is irrelevant to both conclusions.

Facts & Assumptions

Given: The integrable f, its integral function F, and the indicated one-sided limits.

[L2]

The right-limit condition says that for every ε>0, f(x)L+<ε throughout a sufficiently short interval to the right of c; the left version is analogous (The left and right limits of f at c, as limits of the restrictions of f to A(,c) and A(c,)).

Proof

technique · epsilon-delta
1.1

Assume the right limit exists and fix ε>0. By [L2], choose δ>0 so that f(x)L+<ε whenever c<x<c+δ within [a,b].

givenL2
1.2

For the left limit, take h<0, rewrite the same quotient using the oriented integral over [c+h,c], and apply [L2] and [L3]; its limit is L.

givenL1L2L3
2.1

For 0<h<δ with c+hb, [L1] and linearity give F(c+h)F(c)hL+=1hcc+h(fL+).

step 1.1L1algebra
3.1

By [L3], the absolute value in step 2.1 is at most ε. Hence the right difference quotient tends to L+.

step 1.1step 2.1L3
4.1

At an interior point a two-sided derivative would have to equal both one-sided derivatives, so unequal L+ and L preclude it. Neither estimate refers to f(c).

step 3.1step 1.2

Depends on

Used by

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