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Entropy dissipation of the orthogonal finite-volume viscous scheme
Statement
Every differentiable solution of One-dimensional orthogonal finite-volume viscous scheme with satisfies
The endpoint viscous fluxes vanish by definition, and the face quadratic forms use the state block .
Facts & Assumptions
Given: , an integer , , differentiable cell states , and the finite-volume viscous ODE in One-dimensional orthogonal finite-volume viscous scheme.
Positive-semidefinite entropy-variable factorization of viscous flux: each one-direction state block is symmetric positive semidefinite.
Proof
For the total conservative state, substitute [F1] and telescope the finite sum: .
Since by [F3], the chain rule gives . Substituting [F1] cancels the factors and gives .
At each interior face , the two adjacent cells contribute . The boundary terms vanish by [F1]. Substituting the face flux gives the exact negative sum in the Statement.
Each midpoint state is admissible by the convexity built into [F1], and its matrix block is positive semidefinite by [F2]. Thus every face term is nonnegative because . This proves the entropy inequality, including the case when the face sum is empty.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- R. Eymard, T. Gallouët, and R. Herbin, Finite Volume Methods, January 2019 updated author text, complete manuscript (standard reference, not scraped)
- Jérôme Droniou, Finite volume schemes for diffusion equations: introduction to and review of modern methods, 2014, complete preprint (standard reference, not scraped)