Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Projection onto a nonempty closed convex set

Statement

Assume the Axiom of Countable Choice. Let H be a real or complex Hilbert space, let CH be nonempty, closed and convex, and let xH. Then there is exactly one point pC with xp=infcCxc, that is, a unique nearest point of C to x.

Facts & Assumptions

[A1]

A Hilbert space is an inner-product space complete for its induced norm: every Cauchy sequence converges to a point of the space (Hilbert space).

[A2]

Every nonempty real set bounded below has an infimum, characterised by points arbitrarily close from above (Every nonempty set bounded below has an infimum, Epsilon characterisation of the infimum).

[A3]

Countable Choice selects a point from each set of a countable family of nonempty sets (The Axiom of Countable Choice (ACω)).

[A4]

A minimizing sequence in a nonempty convex set is Cauchy (A minimizing sequence in a convex set is Cauchy).

[A5]

C is convex and dxc for every cC (Convex sets and continuous real-hyperplane separation in a normed space, Greatest lower bound (infimum)). A closed set equals its closure, and a point lies in the closure whenever every ball about it meets the set (The closure of a nonempty A is {x:d(x,A)=0}, equals A together with its limit points, and is the smallest closed superset); limits in a metric space are unique (A sequence in a metric space has at most one limit).

[A6]

Norm distance is continuous: uvuv (The reverse triangle inequality in a normed space).

[A7]

Convergence of a sequence of reals to L means that for every ε>0 the terms are eventually within ε of L, and for every ε>0 some 1/n is below ε (Limits and Cauchy sequences of reals, For every ε>0 in a complete ordered field there is a natural n1 with 1/n<ε).

[A8]

Every inner-product norm satisfies the parallelogram law (The parallelogram law).

Proof

technique · direct

Given: Countable Choice, a real or complex Hilbert space H, a nonempty closed convex set CH and a vector xH.

1.1

The set D={xc:cC} is nonempty and bounded below by 0, so d=infD exists and for every n some cC has xc<d+1/(n+1) by the epsilon characterisation of the infimum.

A2
2.1

Countable Choice selects for every n a point cnC with xcn<d+1/(n+1), the sets being nonempty by step 1.1.

step 1.1A3
3.1

Then 0xcnd<1/(n+1) for every n, so xcnd by the Archimedean reciprocal bound; hence (cn) is Cauchy by the minimizing-sequence lemma, completeness of H gives a limit pH, and closedness of C places p in C.

step 2.1A1A4A5A7
4.1

Moreover xp=d: norm continuity along the limit gives xpxcnpcn0, and a limit of the sequence xcn is unique.

step 3.1A5A6
5.1

If p,qC both satisfy xp=xq=d, then the midpoint 12(p+q) lies in C by convexity, so x12(p+q)d, and the parallelogram law gives pq2=2xp2+2xq24x12(p+q)24d24d2=0, whence p=q: the nearest point is unique.

step 4.1A5A8algebra

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Sources