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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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Pullback of modules is left adjoint to pushforward

Statement

Let

(f,f♯):(X,OX)⟶(Y,OY)

be a morphism of ringed spaces, let G be an OY-module, and let F be an OX-module. Then there is a natural bijection Hom⁡OX(f∗G,F)≅Hom⁡OY(G,f∗F).

Facts & Assumptions

Given: A morphism of ringed spaces (f,f♯):(X,OX)→(Y,OY), an OY-module G, and an OX-module F.

[F1]

The pullback is f∗G=OX⊗f−1OYf−1G (Pullback of a module along a morphism of ringed spaces).

[L1]

Extension of scalars is left adjoint to restriction of scalars for a ring map (Extension of scalars is left adjoint to restriction of scalars).

[L2]

Inverse image is left adjoint to direct image on sheaves (Inverse image is left adjoint to direct image on sheaves).

[L3]

A morphism from a presheaf to a sheaf factors uniquely through the sheafification (Sheafification is left adjoint to the inclusion of sheaves into presheaves).

Proof

technique · direct
1.1F1L3given

Let α:f∗G→F be an OX-linear morphism. By [F1] and [L3], α is equivalent to a morphism from the tensor-product presheaf U⟼OX(U)⊗(f−1OY)(U)(f−1G)(U) into the sheaf F.

1.2F1L1L2L3givenconstruct

Conversely, let β:G→f∗F be an OY-linear morphism. By [L2], it corresponds to an f−1OY-linear morphism β~:f−1G→F. Applying [L1] on each open set gives a morphism from the tensor-product presheaf of [F1] into F, and then [L3] factors it uniquely through the sheafification f∗G. This yields an OX-linear morphism α:f∗G→F.

2.1L1step 1.1

Applying [L1] on each open set U⊆X converts the map of step 1.1 into an (f−1OY)(U)-linear map (f−1G)(U)→F(U), compatible with restriction. Hence step 1.1 is equivalent to an f−1OY-linear sheaf morphism α~:f−1G→F.

3.1L2step 2.1

By [L2], the underlying sheaf morphism α~ corresponds to a sheaf morphism β:G→f∗F. Because the maps in step 2.1 are (f−1OY)(U)-linear, the corresponding components βV are OY(V)-linear. Thus β is a morphism of OY-modules.

4.1step 2.1step 3.1step 1.2∎

The constructions in steps 3.1 and 1.2 are inverse because each stage is built from an adjunction with the standard mutually inverse formulas. Therefore Hom⁡OX(f∗G,F)≅Hom⁡OY(G,f∗F) naturally in both variables.

Depends on

Used by

Dependency tree · two levels

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Sources