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Sheafification is left adjoint to the inclusion of sheaves into presheaves

Statement

Let F be a presheaf on a topological space X, let ηF:F→aF be its sheafification map, and let G be a sheaf on X. Then every morphism of presheaves φ:F⟶G factors uniquely through ηF: there is a unique morphism of sheaves φ‾:aF⟶G such that φ=φ‾∘ηF.

Facts & Assumptions

Given: A presheaf F, a sheaf G, and a morphism φ:F→G.

[F1]

Sheafification is the double plus construction with unit ηF:F→aF (Sheafification of a presheaf).

[L1]

The first plus construction is separated (The first plus construction is separated and preserves stalks).

[L2]

The second plus construction is a sheaf (The second plus construction is a sheaf).

Proof

technique · direct
1.1F1L1L2givenconstruct

Let σ∈F+(U) be represented by sections si∈F(Ui) on an open cover U=⋃iUi. The sections φUi(si)∈G(Ui) have equal germs on overlaps because the si do. Since G is a sheaf, they glue uniquely to a section φU+(σ)∈G(U). This is independent of the chosen presentation because equivalent presentations have the same germs at every point, and a sheaf is separated. Thus φ extends uniquely to a morphism φ+:F+→G.

2.1F1step 1.1construct

Apply the same construction again to the morphism φ+:F+→G. Because G is already a sheaf, this yields a morphism φ‾:(F+)+=aF⟶G whose restriction along the second unit map is φ+. Composing with the first unit map gives φ‾∘ηF=φ.

3.1F1L2step 2.1

To prove uniqueness, let ψ,ψ′:aF→G satisfy ψ∘ηF=ψ′∘ηF. Fix an open set U and a section σ∈aF(U). By [F1], σ is represented locally by sections of F+, and each such local F+-section is itself locally represented by sections of F. Therefore U admits an open cover {Ui} and sections si∈F(Ui) such that σ∣Ui=ηF,Ui(si) for every i. On each Ui the hypothesis gives ψU(σ)∣Ui=ψUi(ηF,Ui(si))=ψUi′(ηF,Ui(si))=ψU′(σ)∣Ui. Since G is a sheaf, locality forces ψU(σ)=ψU′(σ). Thus ψ=ψ′.

4.1F1step 2.1step 3.1∎

Steps 2.1 and 3.1 prove that every morphism F→G factors uniquely through ηF. This is the stated adjoint universal property.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources