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HHL capped postselection amplification cost

Statement

For the OP5 HHL attempt with p≥1/(16κ2) and failure target 0<ρ<1, the capped schedule uses at most 2RK=O(κ(1+log⁡(1/ρ))) calls in total to V and V†, where K=⌈4κ⌉ and R=⌈16ln⁡(1/ρ)⌉+16. Thus it uses O(κ(1+log⁡(1/ρ))) calls to the supplied preparation form (the tagged BA in dilation mode) and separately to its inverse, multiplied by their actual supplied costs.

Facts & Assumptions

Given: OP5 access costs and the lower success bound.

[F1]

Finite capped amplification succeeds with a supplied lower bound: each round uses at most K calls to V and at most K calls to V†, over R rounds.

[F2]

HHL finite sine-window phase-estimation algorithm: each V contains one call to the supplied preparation form and each V† one call to its inverse. In rectangular mode this form is the tagged BA from the Definition, and its controlled/gate cost is the actual declared cost for that access.

[F3]

Circuit-family and computation cost model: sequential costs add and every inverse or controlled access has its own declared cost.

Proof

1.1F1algebra

By [F1], the total number of preparation and inverse-preparation calls is bounded separately by RK each. Since K=⌈4κ⌉≤5κ for κ≥1 and R≤16ln⁡(1/ρ)+17, each count is O(κ(1+log⁡(1/ρ))) with an absolute constant.

2.1F2F3step 1.1algebra∎

Each preparation call invokes the supplied preparation form once, and each inverse preparation invokes its actual inverse once by [F2]. Their circuit/query/gate costs therefore multiply the two counts separately and add by [F3]. No call to a controlled form, simulator, reflection, or verifier is included unless it appears in the declared circuit.

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Sources